数据结构基础_二分法查找
公共引用头文件common.h
#include <stdio.h> #include <stdlib.h> /** * * @param p 待申请内存的指针 * @param s 申请内存大小 */ #define MALLOC(p,s) \ if(!((p) = malloc(s)) ){\ fprintf(stderr, "Insufficient memory");\ exit(EXIT_FAILURE);\ } /** * 交换两个数 宏定义方式 * @param x 交换数1 * @param y 交换数2 * @param t 临时变量 */ #define SWAP(x,y,t) ((t) = (x), (x) = (y), (y) = (t)) void swap(int *x,int *y){ int temp = *x; *x = *y; *y =temp; } #define COMPARE(x, y) ( ((x) < (y)) ? -1 : ((x) == y) ? 0 : 1 ) int compare(int x,int y){ if(x < y){ return -1; }else if(x == y){ return 0; }else{ return 1; } }
1. 一般方法
#include "common.h" int binSearch(int list[], int searchNum, int left, int right){ int middle; while(left <= right){ middle = (left + right) / 2; switch(COMPARE(list[middle], searchNum)){ case -1: left = middle + 1; break; case 0: return middle; case 1: right = middle - 1; break; } } return -1; } int main(){ int list[] = {10,20,40,50,36,40,50,20}; int left = 0; int right = 8; int i; int searchNum = 20; int position; printf("目标数组为\n"); for(i = 0; i < 8; i++) { printf("%d ", list[i]); } position = binSearch(list, searchNum, left, right); printf("\n%d在数组中的位置为第%d个", searchNum, position + 1); return 0; }
2. 递归方法
int binSearch2(int list[], int searchNum, int left, int right){ int middle; while(left <= right){ middle = (left + right) / 2; switch(COMPARE(list[middle], searchNum)){ case -1: return binSearch2(list, searchNum, middle + 1, right); case 0: return middle; case 1: return binSearch2(list, searchNum, left, right - 1); } } return -1; }
|
作者:沙漏哟 出处:计算机的未来在于连接 本文版权归作者和博客园共有,欢迎转载,请留下原文链接 微信随缘扩列,聊创业聊产品,偶尔搞搞技术 |