摘要: 9 then temp2=mid(cstr(temp1),2,1) if temp2>4 then temp3=(int(temp1/(10^(len(cstr(temp1))-1)))+1)*10^(len(cstr(temp1))-1) else temp3=(int(temp1/(10^(len(cstr(temp1))-1)))+0.5)*10^(len(cstr... 阅读全文
posted @ 2007-09-30 14:21 Derek 阅读(255) 评论(0) 推荐(0) 编辑