第七次作业
1.编写一个简单程序,要求数组长度为5,静态赋值10,20,30,40,50,在控制台输出该数组的值。
package ydy3;
import java.util.Scanner;
public class test3{
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int[] arr=new int[]{10,20,30,40,50};
for(int i=0;i<arr.length;i++)
{
System.out.println(arr[i]+"");
}
}
}
2.编写一个简单程序,要求数组长度为5,动态赋值10,20,30,40,50,在控制台输出该数组的值。
package ydy3;
import java.util.Scanner;
public class test3{
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int[] a = new int[6];
for (int i = 1; i < a.length; i++)
{
a[i]+=a[i-1]+10;
System.out.print(a[i] + " ");
}
}
}
3.编写一个简单程序,定义整型数组,里面的元素是{23,45,22,33,56},求数组元素的和、平均值
package ydy3;
import java.util.Scanner;
public class test3{
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int[] a = new int[]{23,45,22,33,56};
int sum=0,ave=0;
for (int i = 0; i < a.length; i++)
{
sum+=a[i];
}
ave=sum/5;
System.out.println(sum + " " + ave);
}
}
4.在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标。
package ydy3;
import java.util.Scanner;
public class test3{
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int[] a = new int[] { 18, 25, 7, 36, 13, 2, 89, 63 };
int max = a[0];
for (int i = 0; i < a.length; i++) {
if (max < a[i])
{
max = a[i];
}
}
System.out.println("最大值是:" + max);
int count = 0;
for (int i = 0; i < a.length; i++) {
if (a[i] == max) {
System.out.println("下标值是:" + count);
}
count++;
}
}
}
5. 将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问)
package ydy3;
import java.util.Scanner;
public class test3{
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int [] a = new int [] {4,1,3,5,9,2,1};
int t;
for(int i = 0; i < a.length / 2; i ++) {
t = a[i];
a[i] = a[a.length - 1 - i];
a[a.length - 1 - i] = t;
}
for(int i = 0; i < a.length; i ++) {
System.out.print(a[i] + ", ");
}
}
}