1064 Complete Binary Search Tree
题目:
A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
- Both the left and right subtrees must also be binary search trees.
A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.
Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (≤1000). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.
Output Specification:
For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.
Sample Input:
10
1 2 3 4 5 6 7 8 9 0
Sample Output:
6 3 8 1 5 7 9 0 2 4
思路:
1、BST二叉搜索树的中序遍历数组一定是单调递增的,因此我们将结点从小到大排序即可得到二叉搜索树的中序遍历数组
2、已知中序/前序/后序遍历,直接求层序遍历(前提是完全二叉树)
int inOrder[1005], levelOrder[1005]; int k = 1; void level(int root){ if(root>n)return; level(root * 2); levelOrder[root] = inOrder[k++]; level(root * 2 + 1); }
代码:
#include<stdio.h> #include<iostream> #include<algorithm> using namespace std; int n, k = 1; int inOrder[1005], levelOrder[1005]; void level(int root){ if(root>n)return; level(root * 2); levelOrder[root] = inOrder[k++]; level(root * 2 + 1); } int main(){ scanf("%d", &n); for(int i = 1; i <= n; i++){ scanf("%d", &inOrder[i]); } sort(inOrder + 1, inOrder + n + 1); level(1); for(int i = 1; i <= n; i++){ if(i != 1){ printf(" "); } printf("%d", levelOrder[i]); } return 0; }
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