150. Evaluate Reverse Polish Notation

问题描述：

Evaluate the value of an arithmetic expression in Reverse Polish Notation.

Valid operators are +, -, *, /. Each operand may be an integer or another expression.

Note:

• Division between two integers should truncate toward zero.
• The given RPN expression is always valid. That means the expression would always evaluate to a result and there won't be any divide by zero operation.

Example 1:

Input: ["2", "1", "+", "3", "*"]
Output: 9
Explanation: ((2 + 1) * 3) = 9

Example 2:

Input: ["4", "13", "5", "/", "+"]
Output: 6
Explanation: (4 + (13 / 5)) = 6

Example 3:

Input: ["10", "6", "9", "3", "+", "-11", "*", "/", "*", "17", "+", "5", "+"]
Output: 22
Explanation: 
  ((10 * (6 / ((9 + 3) * -11))) + 17) + 5
= ((10 * (6 / (12 * -11))) + 17) + 5
= ((10 * (6 / -132)) + 17) + 5
= ((10 * 0) + 17) + 5
= (0 + 17) + 5
= 17 + 5
= 22

 

解题思路：

这个是操作符在后面的形式。

我们可以用栈来辅助进行计算：

　　当遇见数字字符串时，需要转换成int并进行压栈；

　　当遇见操作符字符串时，取出栈顶前两个元素，计算后将结果压栈

 

代码：

class Solution {
public:
    int evalRPN(vector<string>& tokens) {
        stack<int> stk;
        int ret = 0;
        for(int i = 0; i < tokens.size(); i++){
            if(tokens[i].size() == 1){
                int isOp = isOperator(tokens[i]);
                if(isOp >= 0){
                    int a = stk.top();
                    stk.pop();
                    int b = stk.top();
                    stk.pop();
                    if(isOp == 0){
                        stk.push(a+b);
                    }else if(isOp == 1){
                        stk.push(b-a);
                    }else if(isOp == 2){
                        stk.push(b*a);
                    }else if(isOp == 3){
                        stk.push(b / a);
                    }
                    continue;
                }
            }
            int num = stoi(tokens[i]);
            stk.push(num);
        }
        return stk.top();
    }
private:
    int isOperator(string s){
        if(s == "+")
            return 0;
        if(s == "-")
            return 1;
        if(s == "*")
            return 2;
        if(s == "/")
            return 3;
        return -1;
    }
};