怎样获取获取GridView里面的label

GridView如下:

<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" OnRowDataBound="GridView1_RowDataBound">
      
<Columns>
 
<asp:BoundField DataField="errornum" HeaderText="错误数" />   //control[0]
 
<asp:BoundField DataField="rightnum" HeaderText="正确数" />   //controls[1]
 
<asp:BoundField DataField="adatatime" HeaderText="答题时间" /> //control[2]
    
  
<asp:TemplateField HeaderText="正确率">                                       //control[3]
      
<ItemTemplate>
       
<asp:Label ID="bfb" runat=server>aa</asp:Label>
      
</ItemTemplate>
      
</asp:TemplateField>

      
</Columns>
      
</asp:GridView>

我们现在要在 GridView1_RowDataBound(object sender, GridViewRowEventArgs e)事件中获取
<asp:Label ID="bfb" runat=server>aa</asp:Label>的引用
代码如下:

1     protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
2     {
3         if (e.Row.RowType == DataControlRowType.DataRow)
4         {
5              Label bfb = (Label)e.Row.Controls[3].FindControl("bfb");
  
6 
7         }
8 
9     }

上面的第五行代码 Label bfb = (Label)e.Row.Controls[3].FindControl("bfb");
也可以改为     Label bfb = (Label)e.Row.Controls[3].Controls[1];
因为

<asp:TemplateField HeaderText="正确率">  </asp:TemplateField>
包含
-System.Web.UI.LiteralControl      //controls[0]
-System.Web.UI.WebControls.Label  //controls[1]
-System.Web.UI.LiteralControl      //control[2]
三个子控件,所以label 的index为1。





 

posted on 2006-03-26 00:57  Sunny  阅读(1110)  评论(0编辑  收藏  举报