CommandLineRunner的使用
CommandLineRunner介绍
问题:在项目启动时,我们需要加载或者预先完成某些动作,该怎么办呢?
解决办法:在springBoot中是实现CommandLineRunner接口类
CommandLineRunner翻译过来就是“命令行运行者”,很形象😏
主要有以下方式:
(1)
@Component
(2)@SpringBootApplication
(3)声明一个实现了CommandLineRunner接口的Bean
1. @Component实现
具体代码如下:
@SpringBootApplication
public class Demo03Application {
public static void main(String[] args) {
System.out.println("step 1: The Service will start");
SpringApplication.run(Demo03Application.class, args);
System.out.println("step 5: The Service has started");
}
}
@Component
@Order(1)
class Runner1 implements CommandLineRunner {
@Override
public void run(String... args) throws Exception {
System.out.println("step 3: The Runner1 run...");
}
}
@Component
@Order(2)
class Runner2 implements CommandLineRunner {
@Override
public void run(String... args) throws Exception {
System.out.println("step 4: The Runner1 run...");
}
}
运行结果如图所示:
由以上代码可以发现:在SpringApplication.run运行完之后才会运行自己创建的实现类,并且自己的实现类通过@Order()
注解控制顺序,数字越小越靠前。
思考一下为什么要加@Component注解呢?
(1)、加入@Component注解后,就可以将对象交给spring管理。
(2)、当Spring 容器初始化完成后, Spring会遍历所有实现CommandLineRunner接口的类, 并运行其run() 方法.
2. @SpringBootApplication实现
具体代码如下:
@SpringBootApplication
public class Demo03Application implements CommandLineRunner{
public static void main(String[] args) {
System.out.println("step 1: The Service will start");
SpringApplication.run(Demo03Application.class, args);
System.out.println("step 5: The Service has started");
}
@Override
public void run(String... args) throws Exception {
System.out.println("app start");
}
}
运行结果如图所示:
3. @Bean实现
具体代码如下:
@SpringBootApplication
public class SpringBootWebApplication extends SpringBootServletInitializer {
public static void main(String[] args) throws Exception {
SpringApplication.run(SpringBootWebApplication.class, args);
}
@Bean
public ApplicationStartupRunner schedulerRunner() {
return new ApplicationStartupRunner();
}
}
public class ApplicationStartupRunner implements CommandLineRunner {
protected final Log logger = LogFactory.getLog(getClass());
@Override
public void run(String... args) throws Exception {
logger.info("Application Started !!");
}
}
环环无敌大可爱
😄