python3--basic2
2019-07-12 23:46 yanux 阅读(200) 评论(0) 编辑 收藏 举报# 1,2,3,4,5,6,7,8,9 print all the non-duplicated 2 bits numbers consist of these numbers; # print the counter of the numbers # L = [] # for i in range(1,10,1): # for j in range(1,10,1): # if i != j: # L.append(10*i+j) # # print(L) # print(len(L)) # if the characters are: 1,2,3,6,8,9 a,b,d,e,f, print all the strings with 2 chars; # a1 and 1a is looked as repeated string # save the string into a list # print the counter of the strings lst = [1, 2, 3, 6, 8, 9, 'a', 'b', 'd', 'e', 'f'] L = [] for i in range(0, len(lst)-1): for j in range(i+1, len(lst)): s = str(lst[i]) + str(lst[j]) L.append(s) print(L) print(len(L))