Spring+hibernate集成方式(二)
第二种集成方案原理:将Struts的Action交给Spring创建,这样,业务逻辑对象将会被注入,这样就避免了以来查找。其中代理Action的作用取得BeanFactory,然后到ioc容器中将本次请求对应的Action取出
当客户端发送请求时,仍然由web.xml转到ActionServlet,在这里,struts-config.xml都将其转到DelegatingAction中,将取得具体Action对象的操作交给Spring框架来实现。在applicationContext中,由url字符串的不同,将具体的ActionBean创建好。我们在代理Action中,拿到Beanfactory,然后,根据需求取得相应的Action即可。
部分代码实现:
web.xml
<servlet> <servlet-name>action</servlet-name> <servlet-class>org.apache.struts.action.ActionServlet</servlet-class> <init-param> <param-name>config</param-name> <param-value>/WEB-INF/struts-config.xml</param-value> </init-param> </servlet> <!-- Standard Action Servlet Mapping --> <servlet-mapping> <servlet-name>action</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> <context-param> <param-name>contextConfigLocation</param-name> <param-value>classpath:applicationContext-*.xml</param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener>
struts-config.xml
<struts-config> <form-beans> <form-bean name="loginForm" type="com.bjpowernode.usermgr.web.forms.LoginActionForm"/> </form-beans> <action-mappings> <action path="/login" type="org.springframework.web.struts.DelegatingActionProxy" name="loginForm" scope="request" > <forward name="success" path="/login_success.jsp"/> </action> </action-mappings> <message-resources parameter="MessageResources" /> </struts-config>
LoginActionForm.java
publicclass LoginActionForm extends ActionForm { private String username; private String password; public String getUsername() { returnusername; } publicvoid setUsername(String username) { this.username = username; } public String getPassword() { returnpassword; } publicvoid setPassword(String password) { this.password = password; } }
LoginAction.java
publicclass LoginAction extends Action { private UserManager userManager; @Override public ActionForward execute(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response) throws Exception { LoginActionForm laf = (LoginActionForm)form; String username = laf.getUsername(); String password = laf.getPassword(); userManager.login(username, password); return mapping.findForward("success"); } publicvoid setUserManager(UserManager userManager) { this.userManager = userManager; } }
applicationContext.xml
<bean name="/login" class="com.bjpowernode.usermgr.web.actions.LoginAction" scope="prototype"> <property name="userManager" ref="userManager"/> </bean>
<bean id="userManager" class="com.bjpowernode.usermgr.manager.UserManagerImpl"/>