面试题 多线程并发 两个线程交替打印 三个线程交替打印

 

 两个线程交替打印

public class Test2 {
    private static int count = 0;
    private final static Object lock = new Object();
    static class TurningRunner implements Runnable {
        @Override
        public void run() {
            while (count <= 10) {
                // 获取锁
                synchronized (lock) {
                    // 拿到锁就打印
                    System.out.println(Thread.currentThread().getName() + ":" + count++);
                    // 唤醒其他线程
                    lock.notifyAll();
                    try {
                        // 如果任务还没有结束,则让出当前的锁并休眠
                        if (count <= 10) {
                            lock.wait();
                        }
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }
            }
        }
    }

    public static void main(String[] args) throws InterruptedException {
        Thread a = new Thread(new TurningRunner(), "偶数");
        Thread b = new Thread(new TurningRunner(), "奇数");
        a.start();
        b.start();
    }
}

 三个线程交替打印

import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;

public class PrintNumber extends Thread {
/**
* 多个线程共享这一个sequence数据
*/
private static int sequence = 1;
private static final int SEQUENCE_END =75;

private int id;
private static ReentrantLock lock = new ReentrantLock();
private static Condition[] conditions = {lock.newCondition(),lock.newCondition(),lock.newCondition()};

private PrintNumber(int id) {
this.id = id;
this.setName("线程:" + (id + 1));
}

@Override
public void run() {
while (sequence < SEQUENCE_END) {
lock.lock();
try {
//对序号取模,如果不等于当前线程的id,则先唤醒其他线程,然后当前线程进入等待状态
while ((sequence/5) % conditions.length != id) {
conditions[(id + 1) % conditions.length].signal();
conditions[id].await();
}
for(int i = 0; i < 5; i++)
{
System.out.println(Thread.currentThread().getName() + " " + sequence++);
}
//唤醒当前线程的下一个线程
conditions[(id + 1) % conditions.length].signal();
//当前线程进入等待状态
conditions[id].await();
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
//将释放锁的操作放到finally代码块中,保证锁一定会释放
lock.unlock();
}
}
//数字打印完毕,线程结束前唤醒其余的线程,让其他线程也可以结束
end();
}

private void end() {
lock.lock();
conditions[(id + 1) % conditions.length].signal();
conditions[(id + 2) % conditions.length].signal();
lock.unlock();
}

public static void main(String[] args) {
int threadCount = 3;
// ReentrantLock lock = new ReentrantLock();
// Condition[] conditions = new Condition[threadCount];
// for (int i = 0; i < threadCount; i++) {
// conditions[i] = lock.newCondition();
// }
PrintNumber[] printNumbers = new PrintNumber[threadCount];
for (int i = 0; i < threadCount; i++) {
printNumbers[i] = new PrintNumber(i);
}
for (PrintNumber printNumber : printNumbers) {
printNumber.start();
}
}

}

 

posted @ 2020-02-20 17:58  yanhowever  阅读(1668)  评论(0编辑  收藏  举报