复制对象属性:只复制需要的属性值,目标对象中原来的值不变(反射)

使用反射(性能很差,自测是cglib-beanmap性能的50分之1左右):

/**
     * 复制对象属性:只复制需要的属性值,目标对象中原来的值不变
     * 只适用于2个相同对象
     * @param from 要复制的对象
     * @param to 目标对象
     * @throws Exception
     */
    @SuppressWarnings("unchecked")
    public static void copyPropertiesExclude(Object from, Object to) throws Exception {
        if(!from.getClass().equals(to.getClass())){
            throw new RuntimeException("对象不是同一类型,fromClass:"+from.getClass()+",toClass:"+to.getClass());
        }
        Method[] fromMethods = from.getClass().getDeclaredMethods();
        Method[] toMethods = to.getClass().getDeclaredMethods();
        Method fromMethod = null, toMethod = null;
        String fromMethodName = null, toMethodName = null;
        for (int i = 0; i < fromMethods.length; i++) {
            fromMethod = fromMethods[i];
            fromMethodName = fromMethod.getName();
            if (!fromMethodName.contains("get")) {
                continue;
            }
            toMethodName = "set" + fromMethodName.substring(3);
            toMethod = findMethodByName(toMethods, toMethodName);
            //如果方法为null,不处理
            if (toMethod == null) {
                continue;
            }
            Object value = fromMethod.invoke(from, new Object[0]);
            //如果值为空,不处理
            if(value == null) {
                continue;
            }
            //集合类判空处理
            if(value instanceof Collection) {
                Collection newValue = (Collection)value;
                if(newValue.size() <= 0)
                    continue;
            }
            toMethod.invoke(to, new Object[] {value});
        }
    }

    /**
     * 从方法数组中获取指定名称的方法
     *
     * @param methods
     * @param name
     * @return
     */
    public static Method findMethodByName(Method[] methods, String name) {
        for (int j = 0; j < methods.length; j++) {
            if (methods[j].getName().equals(name))
                return methods[j];
        }
        return null;
    }

 

posted @ 2016-08-17 09:23  艺言弈行  阅读(1101)  评论(0编辑  收藏  举报