将一个链表中倒数第n个节点删除

Given a linked list, remove the nth node from the end of list and return its head.

For example,

   Given linked list: 1->2->3->4->5, and n = 2.

   After removing the second node from the end, the linked list becomes 1->2->3->5.

Note:
Given n will always be valid.
Try to do this in one pass.

posted @ 2015-12-09 10:00  code_yang  阅读(143)  评论(0编辑  收藏  举报