摘要：
/*ID:linyvxi1LANG:C++TASK:friday*/#include <stdio.h>int day_map[]={0,31,28,31,30,31,30,31,31,30,31,30,31};int final[8]={0};bool leap_year(int n){ if(n%400==0||(n%4==0&&n%100!=0)) return true; return false;}int cal(int year){ int i,days=0; for(i=1900;i<year;i++){ days+=leap_year(i)?3 阅读全文