ZJU PAT 1008

 http://pat.zju.edu.cn/contests/pat-practise/1008
 1 #include <stdio.h>
2 int number[102];
3 int main()
4 {
5 int N;
6 scanf("%d",&N);
7 int i;
8 for(i=0;i<N;i++)
9 scanf("%d",&number[i]);
10 int sum=0;
11 sum+=6*number[0];
12 for(i=1;i<N;i++){
13 if(number[i]>number[i-1])
14 sum+=6*(number[i]-number[i-1]);
15 else sum+=4*(number[i-1]-number[i]);
16 }
17 printf("%d\n",sum+5*N);
18 }


posted @ 2011-10-09 12:11  linyvxiang  阅读(173)  评论(0编辑  收藏  举报