摘要: 一、简单代码 $fileImage = 'https://域名/202109/11/134923278422.png'; $imgPathInfo =pathinfo($fileImage); $basename = $imgPathInfo['filename'].'png'; $filename 阅读全文
posted @ 2021-09-13 09:11 样子2018 阅读(583) 评论(0) 推荐(0) 编辑