前序遍历和中序遍历树构造二叉树
给出中序遍历:[1,2,3]
和前序遍历:[2,1,3]
. 返回如下的树
2 / \ 1 3
思路:
1、根据前序遍历第一个节点值,创建根节点;
2、找到根节点在中序遍历中的位置i;
3、递归创建左右子树。
问题:第一次提交时方法 copyOfRange 误写成 copyofRange,提示cannot find symbol
import java.util.Arrays;
/**
* Definition of TreeNode:
* public class TreeNode {
* public int val;
* public TreeNode left, right;
* public TreeNode(int val) {
* this.val = val;
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
*@param preorder : A list of integers that preorder traversal of a tree
*@param inorder : A list of integers that inorder traversal of a tree
*@return : Root of a tree
*/
public TreeNode buildTree(int[] preorder, int[] inorder) {
// write your code here
if(inorder.length == 0){
return null;
}
TreeNode r = new TreeNode(preorder[0]);
int i = 0;
while(i < inorder.length){
if(inorder[i] == preorder[0]){
break;
}
i ++;
}
if(i > 0){
int [] pre = Arrays.copyOfRange(preorder,1,i+1);
int [] in = Arrays.copyOfRange(inorder,0,i);
r.left = buildTree(pre,in);
}
if(i < (inorder.length-1)){
int [] pre = Arrays.copyOfRange(preorder,1+i,preorder.length);
int [] in = Arrays.copyOfRange(inorder,i+1,inorder.length);
r.right = buildTree(pre,in);
}
return r;
}
}