树结构的控制

2018-11-13

生成一棵树

如何删除父子节点

 @Override
    @Transactional(rollbackFor = Exception.class)
    public boolean deleteAllById(String depid) {
        try{
            // 得到对象
            FgdjDepartment fgdjDepartment = this.selectById(depid);
            // 判断是否父节点
            if("1".equals(fgdjDepartment.getNotetype())){
                // 父节点,查询出所有的子进行删除
                Map<String,String> map = new HashMap<>();
                map.put("pcode",fgdjDepartment.getCode());
                // 调用方法,查询出所有的子节点
                List<FgdjDepartment> list = this.listByPcode(map);
                // 循环删除节点
                for(FgdjDepartment fgdjDepartment1 : list){
                    this.deleteAllById(fgdjDepartment1.getDepid());
                }
                // 再把自己删除了
                this.deleteById(depid);
            }else {
                // 非父节点
                this.deleteById(depid);
            }
        }catch (Exception e){
            e.printStackTrace();
            return false;
        }
        return true;
    }

 

posted @ 2018-11-13 09:38  闫超辉  阅读(215)  评论(0编辑  收藏  举报