python 循环和file操作实现用户密码输错三次将用户锁定
一、需求
编写登录接口
1.输入用户名密码
2.认证成功后显示欢迎信息
3.输错三次后锁定
二、简单思路
登录,三次密码输入错误锁定用户
1.用户信息文件:存放用户名和密码
2.黑名单文件:将输入三次错误的用户加入此名单,加入此名单的用户将不允许登录
三、具体实现
第一步:在黑名单里检测是否有此用户,如果有则不让登录
第二步:用户名和密码判定
四、代码
count = 0 #记录用户输入密码的次数 flag = 1 #标志位 lock = [] user_pass = [] username = input('please input your name:') #读取黑名单的内容 f = open('black_mingdan','r') lock_file = f.readlines() f.close() #将黑名单文件内容作为列表元素追加到列表中 for i in lock_file: line = i.strip('\n') lock.append(line) #若输入的用户名在黑名单中,如果在则给出提示信息:用户已经被锁定,请联系管理员。 if username in lock: print('User %s Have Been Locked.It is not allow to login,please contact Administrator.' %username) else: #输入的用户名不在黑名单中,则提示用户输入密码信息 while True: count += 1 passwd = input("please input your password:") f = open('user_information','r') user_file = f.readlines() f.close() for i in user_file: user_pass = i.strip().split() #判断输入的用户名==user_pass[0] and 密码==user_pass[1],如果相等,则提示欢迎信息并退出循环,如果不相等则 #结束本次循环 if username == user_pass[0] and passwd == user_pass[1]: print('welcome user %s login !' %username) flag = True break else: continue #若flag为真,则用户名和密码输入正确跳出整个循环体,反之,若用户输入密码错误的次数为3,则给出提示信息:用户已经被锁定 #并将username追加到黑名单中 if flag is True: break else: if count == 3: print('User Have Been try 3 times,Have Been Locked') lock_file = open('black_mingdan','a') #lock_file.write('Have Been Locked User:%s\n' %username) lock_file.write('%s\n' %username) lock_file.close() break
程序执行结果如下:
[root@MiWiFi-R1CM-srv homework]# python3 denglu.py please input your name:zhangsan please input your password:123 welcome user zhangsan login ! [root@MiWiFi-R1CM-srv homework]# python3 denglu.py please input your name:zhangsan please input your password:098 please input your password:678 please input your password:543 User Have Been try 3 times,Have Been Locked [root@MiWiFi-R1CM-srv homework]# python3 denglu.py please input your name:zhangsan User zhangsan Have Been Locked.It is not allow to login,please contact Administrator. [root@MiWiFi-R1CM-srv homework]# cat black_mingdan zhangsan