SQL 绕圈算法？？？
SQL code
--================================================
--绕圈的SQL算法（感觉很笨，不知道有没有更好的算法）
--作者：冷箫轻笛
--日期：2008-02-21
--执行方式（参数必须为整数的平方，但大小并不是无限制的）
--exec raoquan 2500
--================================================
create proc raoquan
(
@num int
)
as
begin
set nocount on
declare @i int
set @i = SQRT(@num)
if CEILING(@i) <> @i
return
declare @table varchar(8000)
declare @insert varchar(8000)
declare @update varchar(8000)
declare @print varchar(8000)
select @insert = '',@update = '',@print = ''
select @table = '
create table #t
('
declare @k int
select @k = 1
while (@k <= @i)
begin
select @table = @table + '
[' + cast(@k as varchar) + '] int,'
select @insert = @insert + 'insert into #t([1]) select ' + cast(@k as varchar) + ' '
select @k = @k + 1
end
select @table = reverse(stuff(reverse(@table),1,1,''))
select @table = @table + '
)
'
select @update = '
declare @r int
declare @c int
select @r = SQRT(' + cast(@num as varchar) + '),@c = 1
declare @i int
select @i = SQRT(' + cast(@num as varchar) + ') + 1
declare @s1 char(1)
select @s1 = ''+''
declare @s2 char(1)
select @s2 = ''c''
declare @s3 int --用于计算符号
select @s3 = 0
declare @len int
select @len = SQRT(' + cast(@num as varchar) + ')
declare @len2 int
select @len2 = 0
while (@len > 0)
begin
if @s3 % 2 = 0
select @len = @len - 1
select @len2 = @len
while(@len2 > 0)
begin
if @s1 = ''+''
begin
if @s2 = ''c''
select @c = @c + 1
else
select @r = @r + 1
end
else
begin
if @s2 = ''c''
select @c = @c - 1
else
select @r = @r - 1
end
declare @sql varchar(8000)
select @sql = ''update #t set ['' + cast(@c as varchar) + ''] = '' + cast(@i as varchar) +
'' where [1] = '' + cast(@r as varchar)
exec (@sql)
select @len2 = @len2 - 1
select @i = @i + 1
end
if @s3/2 % 2 = 1
select @s1 = ''+''
else
select @s1 = ''-''
if @s2 = ''c''
select @s2 = ''r''
else
select @s2 = ''c''
select @s3 = @s3 + 1
end
--select * from #t
'
select @print = '
declare @string varchar(8000)
select @string = ''''
declare @conn varchar(1000)
select @conn =''''
declare @ii int
select @ii = sqrt('+ cast(@num as varchar) + ')
declare @m int
select @m = 1
declare @n int
select @n = 1
while (@ii >= @n)
begin
select @string = ''declare @conn varchar(1000)
select @conn =''
select @m = 1
while (@ii >= @m)
begin
select @string = @string + '' right( SPACE(len(cast('+cast(@num as varchar)+' as varchar))) + cast(['' + cast(@m as varchar) + ''] as varchar), len(cast('+cast(@num as varchar)+' as varchar)) + 1) +''
select @m = @m + 1
end
select @string = reverse(stuff(reverse(@string),1,1,''''))
select @string = @string + '' from #t where [1] = '' + cast(@n as varchar) + ''
print @conn''
exec(@string)
select @n = @n + 1
end
'
exec (@table + @insert + @update + @print)
end
