实验2 字符串和列表

task_1

x = list(range(10))
print('整数输出1: ', end = '')
for i in x:
    print(i, end=' ')
print('\n整数输出2: ', end = '')
for i in x:
    print(f'{i:02d}', end = '-')
print('\n整数输出3: ', end = '')
for i in x[:-1]:
    print(f'{i:02d}', end = '-')
print(f'{x[-1]:02d}')
print('\n字符输出1: ', end = '')
y1 = [str(i) for i in range(10)]
print('-'.join(y1))
print('字符输出2: ', end = '')
y2 = [str(i).zfill(2) for i in range(10)]
print('-'.join(y2))

 

task_2

name_list = ['david bowie', 'louis armstrong', 'leonard cohen', 'bob dylan','cocteau twins']
for name in name_list:
    print(name.title())

print()
name_list_captilize = [name.title() for name in name_list]
print('\n'.join(name_list_captilize))

　　

task_3

name_list = ['david bowie', 'louis armstrong', 'leonard cohen', 'bob dylan','cocteau twins']
name_list.sort()
n = 1
for name in name_list:
    print(n,".",name.title())
    n += 1

　　

task_4

import this

text=("""The Zen of Python, by Tim Peters

Beautiful is better than ugly.
Explicit is better than implicit.
Simple is better than complex.
Complex is better than complicated.
Flat is better than nested.
Sparse is better than dense.
Readability counts.
Special cases aren't special enough to break the rules.
Although practicality beats purity.
Errors should never pass silently.
Unless explicitly silenced.
In the face of ambiguity, refuse the temptation to guess.
There should be one-- and preferably only one --obvious way to do it.
Although that way may not be obvious at first unless you're Dutch.
Now is better than never.
Although never is often better than *right* now.
If the implementation is hard to explain, it's a bad idea.
If the implementation is easy to explain, it may be a good idea.
Namespaces are one honking great idea -- let's do more of those!""")
space=0
line=0
line=text.count('\n')+1
for i in text:
   if i==' ':
      space += 1
cha = len(text)
word = len(text.split())
print('行数:',line)
print('单词数:',word)
print('字符数:',cha)
print('空格数:',space)

 

 task_5

book_list = [['静静的顿河','肖洛霍夫','金人', '人民文学出版社'],
             ['大地之上','罗欣顿.米斯特里','张亦琦', '天地出版社'],
             ['夜航西飞', '柏瑞尔.马卡姆', '陶立夏', '人民文学出版社'],
             ['来自民间的叛逆', '袁越', '','新星出版社'],
             ['科技与恶的距离', '珍妮.克里曼', ' 詹蕎語', '墨刻出版社'],
             ['灯塔','克里斯多夫.夏布特','吕俊君','北京联合出版公司'],
             ['小行星掉在下午','沈大成', '', '广西师范大学出版社']]
for index, i in enumerate(book_list):
    print(f'{index+1}.《{i[0]}》|{i[1]}|{i[2]}')
    print()

 

 

 

 task_6

data = ['99 81 75', '30 42 90 87', '69 50 96 77 89 93', '82 99 78 100']
a = 0
b = len(data)
n = 0
for i in data:
    for x in i.split():
        a += int(x)
        n += 1
v = a/n
print('%.2f'%v)

 

task_7

 

 

words_sensitive_list = ['张三', 'V字仇杀队', '杀']
words_sensitive_list = str(words_sensitive_list)
comments_list = [
    '张三因生命受到威胁正当防卫导致过失杀人，经辩护律师努力，张三不需负刑事责任。',
    '电影<V字仇杀队>从豆瓣下架了',
    '娱乐至死']
for comment in comments_list:
    for word in words_sensitive_list:
        if word in comment :
            comment=comment.replace(word,'*'*len(word))
    print(comment)

 

 

 实验总结：1. 本次实验我学习了Python中字符串的表示，能熟练使用索引、切片、常见字符串操作

2. 知道了Python中列表的表示，熟练使用索引、切片、常见列表操作，能正确使用列表推导式

3. 针对具体问题场景，学会了灵活、组合使用字符串、列表、控制语句编程解决实际问题