剑指offer python版 重建二叉树
from collections import deque class TreeNode(object): """ 二叉树结点定义 """ def __init__(self, x): self.val = x self.left = None self.right = None class Tree(object): """ 二叉树 """ def __init__(self): self.root = None def bfs(self): ret = [] queue = deque([self.root]) while queue: node = queue.popleft() if node: ret.append(node.val) queue.append(node.left) queue.append(node.right) return ret def pre_traversal(self): ret = [] def traversal(head): if not head: return ret.append(head.val) traversal(head.left) traversal(head.right) traversal(self.root) return ret def in_traversal(self): ret = [] def traversal(head): if not head: return traversal(head.left) ret.append(head.val) traversal(head.right) traversal(self.root) return ret def post_traversal(self): ret = [] def traversal(head): if not head: return traversal(head.left) traversal(head.right) ret.append(head.val) traversal(self.root) return ret def construct_tree(preorder=None, inorder=None): """ 构建二叉树 """ if not preorder or not inorder: return None index = inorder.index(preorder[0]) left = inorder[0:index] right = inorder[index+1:] root = TreeNode(preorder[0]) root.left = construct_tree(preorder[1:1+len(left)], left) root.right = construct_tree(preorder[-len(right):], right) return root if __name__ == '__main__': t = Tree() root = construct_tree([1, 2, 4, 7, 3, 5, 6, 8], [4, 7, 2, 1, 5, 3, 8, 6]) t.root = root print t.bfs() print t.pre_traversal() print t.in_traversal() print t.post_traversal()