剑指offer python版 顺时针打印矩阵
def aa(matrix): rows=len(matrix) cols=len(matrix[0]) start=0 ret=[] while start*2 <rows and start*2<cols: bb(matrix,rows,cols,start,ret) start +=1 return ret def bb(matrix,rows,cols,start,ret): row=rows-start-1 col=cols-start-1 for c in range(start,col+1): ret.append(matrix[start][c]) if start <row: for r in range(start+1,row+1): ret.append(matrix[r][col]) if start <row and start<col: for c in range(start,col)[::-1]: ret.append(matrix[row][c]) if start <row and start<col: for r in range(start+1,row)[::-1]: ret.append(matrix[r][start]) a=[[1,2,3], [4,5,6], [7,8,9]] print(aa(a))