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posted @ 2021-10-22 13:56 奇异宝 阅读(123) 评论(0) 推荐(0) 编辑
摘要: memberList.forEach(aa -> {String householderRelation = aa.getHouseholderRelation();}); List<Map<String, String>> list = new ArrayList<>();HashMap<Stri 阅读全文
posted @ 2021-10-22 13:56 奇异宝 阅读(708) 评论(0) 推荐(0) 编辑