POJ1556+几何+dij+线段相交

注意:

注意判断两点是否能相连,需要判断这两点之间是否含有其他的线段。。。

同一列的墙 我用的是flag来标记。。

View Code
  1 /*
  2 dij+两点间距离
  3 */
  4 #include<stdio.h>
  5 #include<string.h>
  6 #include<stdlib.h>
  7 #include<algorithm>
  8 #include<iostream>
  9 #include<math.h>
 10 using namespace std;
 11 
 12 const int maxn = 205;//point number
 13 const int maxm = 105;//line number
 14 const double inf = 99999999;
 15 const double eps = 1e-8;
 16 
 17 struct POINT{
 18     double x,y;
 19     int f;
 20 }S,T;
 21 
 22 struct LINE{
 23     double x1,y1,x2,y2;
 24     int f;
 25 };
 26 
 27 int cnt_line,cnt_point;
 28 POINT point[ maxn ];
 29 LINE line[ maxm ];
 30 double mat[ maxn ][ maxn ];
 31 
 32 double dist( POINT a,POINT b ){
 33     double sum = (a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y);
 34     return sqrt( sum );
 35 }
 36 
 37  double xmult( POINT a,POINT b,POINT c ){
 38      return ( a.x-c.x )*( b.y-c.y )-( a.y-c.y )*( b.x-c.x );
 39  }
 40  
 41  bool inLine( LINE now,POINT p ){
 42      double minx,maxx,miny,maxy;
 43      minx=min( now.x1,now.x2 );
 44      maxx=max( now.x1,now.x2 );
 45      miny=min( now.y1,now.y2 );
 46      maxy=max( now.y1,now.y2 );
 47      if( p.x>=minx&&p.x<=maxx&&p.y>=miny&&p.y<=maxy )
 48          return true;
 49      else
 50          return false;
 51  }
 52  
 53 int Intersection( LINE one,LINE two ){
 54      double d1,d2,d3,d4;
 55      POINT t1,t2,t3,t4;
 56      t1.x = one.x1,t1.y = one.y1,t2.x = one.x2,t2.y = one.y2;
 57      t3.x = two.x1,t3.y = two.y1,t4.x = two.x2,t4.y = two.y2;
 58      d1=xmult( t3,t2,t1 );
 59      d2=xmult( t4,t2,t1 );
 60      d3=xmult( t1,t3,t4 );
 61      d4=xmult( t2,t3,t4 );
 62      if( d1*d2<0&&d3*d4<0 )
 63          return 1;//相互跨过
 64      if( d1==0&&inLine( one,t3 )==true )
 65          return true;
 66      if( d2==0&&inLine( one,t4 )==true )
 67          return true;
 68      if( d3==0&&inLine( two,t1 )==true )
 69          return true;
 70      if( d4==0&&inLine( two,t2 )==true )
 71          return 2;//分别表示某个点在一条直线上的情况
 72      return 0;
 73  }
 74 
 75 void init(){
 76     cnt_line = cnt_point = 0;
 77     for( int i=0;i<maxn;i++ ){
 78         for( int j=0;j<maxn;j++ ){
 79             mat[ i ][ j ] = inf;
 80         }
 81     }
 82 }//init
 83 
 84 void addline( double x1,double y1,double x2,double y2 ){
 85     line[ cnt_line ].x1=x1,line[ cnt_line ].y1=y1;
 86     line[ cnt_line ].x2=x2,line[ cnt_line ].y2=y2;
 87     cnt_line++;
 88 }
 89 
 90 void addpoint( double x,double y ){
 91     point[ cnt_point ].x = x;
 92     point[ cnt_point ].y = y;
 93     cnt_point++;
 94 }
 95 
 96 bool test( POINT a,POINT b ){
 97     LINE tt;
 98     tt.x1 = a.x,tt.y1 = a.y;
 99     tt.x2 = b.x,tt.y2 = b.y;
100     //printf("a.flag:%d b.flag:%d\n",a.f,b.f);
101     for( int i=0;i<cnt_line;i++ ){
102         if( a.f!=line[ i ].f && b.f!=line[ i ].f && Intersection( tt,line[ i ] )==1 )
103             return false;
104     }
105     return true;
106 }
107 
108 double dij( int s,int t ){
109     int vis[ maxn ];
110     double dis[ maxn ];
111     for( int i=0;i<cnt_point;i++ ){
112         dis[ i ] = mat[ s ][ i ];
113         vis[ i ] = 0;
114     }
115     dis[ s ] = 0;
116     vis[ s ] = 1;
117     //double sum = 0;
118     for( int i=0;i<cnt_point;i++ ){
119         int k;
120         double tmax;
121         k =-1,tmax = inf;
122         for( int j=0;j<cnt_point;j++ ){
123             if( vis[ j ]==0&&tmax>dis[ j ] ){
124                 tmax = dis[ j ];
125                 k=j;
126             }
127         }
128         if( k==-1 ) break;
129         vis[ k ] = 1;
130         //sum += tmax;
131         for( int j=0;j<cnt_point;j++ ){
132             if( vis[ j ]==0&&dis[ j ]>dis[ k ]+mat[ k ][ j ] ){
133                 dis[ j ] = dis[ k ]+mat[ k ][ j ];
134             }
135         }
136     }
137     return dis[ t ];
138 }
139 
140 int main(){
141     int m;
142     while( scanf("%d",&m),m!=-1 ){
143         init();
144         S.x = 0.0,S.y = 5.0;
145         T.x = 10.0,T.y = 5.0;
146         if( m==0 ){
147             printf("%.2lf\n",dist( S,T ));
148             continue;
149         }
150         int flag = 0;
151         point[ cnt_point ].f = flag++;
152         addpoint( S.x,S.y );
153         point[ cnt_point ].f = flag++;
154         addpoint( T.x,T.y );//start and end 
155         double x,y1,y2,y3,y4;
156         for( int num=1;num<=m;num++ ){
157             scanf("%lf%lf%lf%lf%lf",&x,&y1,&y2,&y3,&y4);
158             
159             line[ cnt_line ].f = flag;
160             addline( x,0.0,x,y1 );
161             line[ cnt_line ].f = flag;
162             addline( x,y2,x,y3 );
163             line[ cnt_line ].f = flag;
164             addline( x,y4,x,10.0 );//这三条线段归为一类
165             
166             point[ cnt_point ].f = flag;
167             addpoint( x,y1 );
168             point[ cnt_point ].f = flag;
169             addpoint( x,y2 );
170             point[ cnt_point ].f = flag;
171             addpoint( x,y3 );
172             point[ cnt_point ].f = flag;
173             addpoint( x,y4 );//这四个点归为一类
174             
175             flag++;
176         }
177         //printf("flag:%d\ncnt_point:%d\ncnt_line:%d\n",flag,cnt_point,cnt_line);
178         for( int i=0;i<cnt_point;i++ ){
179             for( int j=i+1;j<cnt_point;j++ ){
180                 if( point[ i ].f!=point[ j ].f&&test( point[ i ],point[ j ] )==true ){
181                     mat[ i ][ j ] = mat[ j ][ i ] = dist( point[ i ],point[ j ] );
182                     //printf("mat[ %d ][ %d ] = %.2lf\n",i,j,mat[i][j]);
183                 }
184             }
185         }
186         if( mat[ 0 ][ 1 ]!=inf ){
187             printf("%.2lf\n",mat[ 0 ][ 1 ]);
188             continue;
189         }
190         double ans = dij( 0,1 );
191         printf("%.2lf\n",ans);
192     }
193     return 0;
194 }

哈哈哈哈。。。。代码有点长。。。。。

 

 

posted @ 2013-03-27 18:56  xxx0624  阅读(322)  评论(0编辑  收藏  举报