计算两GPS坐标的实际距离

javascript:

function toRadians(degree) {
return degree * Math.PI / 180;
}
function distance(latitude1, longitude1, latitude2, longitude2) {
// R is the radius of the earth in kilometers
var R = 6371;
var deltaLatitude = toRadians(latitude2-latitude1);
var deltaLongitude = toRadians(longitude2-longitude1);
latitude1 =toRadians(latitude1);
latitude2 =toRadians(latitude2);
var a = Math.sin(deltaLatitude/2) *
Math.sin(deltaLatitude/2) +
Math.cos(latitude1) *
Math.cos(latitude2) *
Math.sin(deltaLongitude/2) *
Math.sin(deltaLongitude/2);
var c = 2 * Math.atan2(Math.sqrt(a),
Math.sqrt(1-a));
var d = R * c;
return d;
}

 

php:

/**
 * 计算两会标之间的距离(米)
 * @param double $lng_a 经度a
 * @param double $lat_a 维度a
 * @param double $lng_b 经度b
 * @param double $lat_b 维度b
 */
function get_distance($lng_a, $lat_a, $lng_b, $lat_b) {
    //R是地球半径(米)
    $R = 6366000;
    $pk = doubleval(180 / 3.14169);
    
    $a1 = doubleval($lat_a / $pk);
    $a2 = doubleval($lng_a / $pk);
    $b1 = doubleval($lat_b / $pk);
    $b2 = doubleval($lng_b / $pk);

    $t1 = doubleval(cos($a1) * cos($a2) * cos($b1) * cos($b2));
    $t2 = doubleval(cos($a1) * sin($a2) * cos($b1) * sin($b2));
    $t3 = doubleval(sin($a1) * sin($b1));
    $tt = doubleval(acos($t1 + $t2 + $t3));

    return $R * $tt;
}

 

sql:

已知坐标:(116.386294,39.923879)

地球半径:6366000米

SELECT id,Lastlongitude,Lastlatitude,
(6366000 * ACOS( 
(COS(RADIANS(116.386042))*COS(RADIANS(39.923927))*COS(RADIANS(Lastlongitude))*COS(RADIANS(Lastlatitude)))+
(COS(RADIANS(39.923927))*SIN(RADIANS(116.386042))*COS(RADIANS(Lastlatitude))*SIN(RADIANS(Lastlongitude)))+
(SIN(RADIANS(39.923927))*SIN(RADIANS(Lastlatitude)))
)) AS distance
FROM drv_driver_location
HAVING distance<10

 

 

posted on 2013-01-22 11:10  一个石头  阅读(862)  评论(0编辑  收藏  举报