实验3 类和对象_基础编程2
实验任务1
bottom.hpp
#pragma once #include <iostream> #include <string> using std::string; using std::cout; // 按钮类 class Button { public: Button(const string &text); string get_label() const; void click(); private: string label; }; Button::Button(const string &text): label{text} { } inline string Button::get_label() const { return label; } void Button::click() { cout << "Button '" << label << "' clicked\n"; }
windows.hpp
#pragma once #include "button.hpp" #include <vector> #include <iostream> using std::vector; using std::cout; using std::endl; // 窗口类 class Window{ public: Window(const string &win_title); void display() const; void close(); void add_button(const string &label); private: string title; vector<Button> buttons; }; Window::Window(const string &win_title): title{win_title} { buttons.push_back(Button("close")); } inline void Window::display() const { string s(40, '*'); cout << s << endl; cout << "window title: " << title << endl; cout << "It has " << buttons.size() << " buttons: " << endl; for(const auto &i: buttons) cout << i.get_label() << " button" << endl; cout << s << endl; } void Window::close() { cout << "close window '" << title << "'" << endl; buttons.at(0).click(); } void Window::add_button(const string &label) { buttons.push_back(Button(label)); }
task1.cpp
#include "window.hpp" #include <iostream> using std::cout; using std::cin; void test() { Window w1("new window"); w1.add_button("maximize"); w1.display(); w1.close(); } int main() { cout << "用组合类模拟简单GUI:\n"; test(); }
运行测试结果截图:
问题1:自定义两个类:分别是button类和window类;
使用标准库类:iostream类、string类和vector类;
组合关系:Window 类中包含了 vector<Button>,表示窗口中有多个按钮。
Window 类的构造函数中创建了一个 Button对象,用于将给定的短语添加到类中定义的成员中。
问题2:不合适。因为没有加const是为了方便修改内部的数据,不加inline是表示成员函数并不要多次调用,没有必要,加了反而会报错。
问题3:用40个*来分隔板块,实现虚拟的窗口。
实验内容2
task2.cpp
#include <iostream> #include <vector> using namespace std; void output1(const vector<int> &v) { for(auto &i: v) cout << i << ", "; cout << "\b\b \n"; } void output2(const vector<vector<int>> v) { for(auto &i: v) { for(auto &j: i) cout << j << ", "; cout << "\b\b \n"; } } void test1() { vector<int> v1(5, 42); const vector<int> v2(v1); v1.at(0) = -999; cout << "v1: "; output1(v1); cout << "v2: "; output1(v2); cout << "v1.at(0) = " << v1.at(0) << endl; cout << "v2.at(0) = " << v2.at(0) << endl; } void test2() { vector<vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}}; const vector<vector<int>> v2(v1); v1.at(0).push_back(-999); cout << "v1: \n"; output2(v1); cout << "v2: \n"; output2(v2); vector<int> t1 = v1.at(0); cout << t1.at(t1.size()-1) << endl; const vector<int> t2 = v2.at(0); cout << t2.at(t2.size()-1) << endl; } int main() { cout << "测试1:\n"; test1(); cout << "\n测试2:\n"; test2(); }
运行测试结果截图:
问题1:line21的功能是创建一个动态数组v1,存放整型类型数据,将5个42存放在v1中
line22的功能是复制v1
line24的功能是修改v1中索引为0的值改为-999
问题2:line32的功能是创建一个动态二维数组v1,存放整型数据,并初始化
line33的功能是创建一个常量动态二维数组v2,将v1的值复制给v2,且不能修改值
line35的功能是修改v1中索引为0的值改为-999
问题3:line39的功能是创建动态数组t1并将v1中索引为0的值赋值给t1
line40的功能是打印t1中的最后一个元素
line42的功能是创建常量动态数组t2并将v2中索引为0的值赋值给t2
line43的功能是打印t2中的最后一个元素
问题4:1)深复制
2)需要,否则用户无法使用const vector调用该方法
实验任务3
vectorInt,hpp
#pragma once #include <iostream> #include <cassert> using std::cout; using std::endl; // 动态int数组对象类 class vectorInt{ public: vectorInt(int n); vectorInt(int n, int value); vectorInt(const vectorInt &vi); ~vectorInt(); int& at(int index); const int& at(int index) const; vectorInt& assign(const vectorInt &v); int get_size() const; private: int size; int *ptr; // ptr指向包含size个int的数组 }; vectorInt::vectorInt(int n): size{n}, ptr{new int[size]} { } vectorInt::vectorInt(int n, int value): size{n}, ptr{new int[size]} { for(auto i = 0; i < size; ++i) ptr[i] = value; } vectorInt::vectorInt(const vectorInt &vi): size{vi.size}, ptr{new int[size]} { for(auto i = 0; i < size; ++i) ptr[i] = vi.ptr[i]; } vectorInt::~vectorInt() { delete [] ptr; } const int& vectorInt::at(int index) const { assert(index >= 0 && index < size); return ptr[index]; } int& vectorInt::at(int index) { assert(index >= 0 && index < size); return ptr[index]; } vectorInt& vectorInt::assign(const vectorInt &v) { delete[] ptr; // 释放对象中ptr原来指向的资源 size = v.size; ptr = new int[size]; for(int i = 0; i < size; ++i) ptr[i] = v.ptr[i]; return *this; } int vectorInt::get_size() const { return size; }
task3.cpp
#include "vectorInt.hpp" #include <iostream> using std::cin; using std::cout; void output(const vectorInt &vi) { for(auto i = 0; i < vi.get_size(); ++i) cout << vi.at(i) << ", "; cout << "\b\b \n"; } void test1() { int n; cout << "Enter n: "; cin >> n; vectorInt x1(n); for(auto i = 0; i < n; ++i) x1.at(i) = i*i; cout << "x1: "; output(x1); vectorInt x2(n, 42); vectorInt x3(x2); x2.at(0) = -999; cout << "x2: "; output(x2); cout << "x3: "; output(x3); } void test2() { const vectorInt x(5, 42); vectorInt y(10, 0); cout << "y: "; output(y); y.assign(x); cout << "y: "; output(y); cout << "x.at(0) = " << x.at(0) << endl; cout << "y.at(0) = " << y.at(0) << endl; } int main() { cout << "测试1: \n"; test1(); cout << "\n测试2: \n"; test2(); }
运行测试结果截图:
问题1:深复制
问题2:不能,返回类型变成int的话代表不能被修改;去掉const,会存在安全隐患,因为成员函数内部数据可能会被修改
问题3:可以,如果将其改为 vectorInt,仍然可以实现类似的功能。在使用 assign () 函数进行赋值操作时,无论是返回引用还是返回一个新的对象,都可以在赋值语句中进行链式操作或者连续赋值
实验任务4
Matrix.hpp
#pragma once #include <iostream> #include <cassert> using std::cout; using std::endl; // 类Matrix的声明 class Matrix { public: Matrix(int n, int m); // 构造函数,构造一个n*m的矩阵, 初始值为value Matrix(int n); // 构造函数,构造一个n*n的矩阵, 初始值为value Matrix(const Matrix &x); // 复制构造函数, 使用已有的矩阵X构造 ~Matrix(); void set(const double *pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值 void clear(); // 把矩阵对象的值置0 const double& at(int i, int j) const; // 返回矩阵对象索引(i,j)的元素const引用 double& at(int i, int j); // 返回矩阵对象索引(i,j)的元素引用 int get_lines() const; // 返回矩阵对象行数 int get_cols() const; // 返回矩阵对象列数 void display() const; // 按行显示矩阵对象元素值 private: int lines; // 矩阵对象内元素行数 int cols; // 矩阵对象内元素列数 double *ptr; }; // 类Matrix的实现 Matrix::Matrix(int n, int m) : lines(n), cols(m) { ptr = new double[n * m]; } Matrix::Matrix(int n) : lines(n), cols(n) { ptr = new double[n * n]; } Matrix::Matrix(const Matrix &x) : lines(x.lines), cols(x.cols) { ptr = new double[lines * cols]; for (int i = 0; i < lines * cols; ++i) { ptr[i] = x.ptr[i]; } } Matrix::~Matrix() { delete[] ptr; } void Matrix::set(const double *pvalue) { for (int i = 0; i < lines * cols; ++i) { ptr[i] = *(pvalue + i); } } void Matrix::clear() { for (int i = 0; i < lines * cols; ++i) { ptr[i] = 0; } } const double& Matrix::at(int i, int j) const { assert(i >= 0 && i < lines && j >= 0 && j < cols); return ptr[i * cols + j]; } double& Matrix::at(int i, int j) { assert(i >= 0 && i < lines && j >= 0 && j < cols); return ptr[i * cols + j]; } int Matrix::get_lines() const { return lines; } int Matrix::get_cols() const { return cols; } void Matrix::display() const { for (int i = 0; i < lines; ++i) { for (int j = 0; j < cols; ++j) { cout << at(i, j) << " "; } cout << endl; } }
task4.cpp
#include "matrix.hpp" #include <iostream> #include <cassert> using std::cin; using std::cout; using std::endl; const int N = 1000; // 输出矩阵对象索引为index所在行的所有元素 void output(const Matrix &m, int index) { assert(index >= 0 && index < m.get_lines()); for(auto j = 0; j < m.get_cols(); ++j) cout << m.at(index, j) << ", "; cout << "\b\b \n"; } void test1() { double x[1000] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; int n, m; cout << "Enter n and m: "; cin >> n >> m; Matrix m1(n, m); // 创建矩阵对象m1, 大小n×m m1.set(x); // 用一维数组x的值按行为矩阵m1赋值 Matrix m2(m, n); // 创建矩阵对象m1, 大小m×n m2.set(x); // 用一维数组x的值按行为矩阵m1赋值 Matrix m3(2); // 创建一个2×2矩阵对象 m3.set(x); // 用一维数组x的值按行为矩阵m4赋值 cout << "矩阵对象m1: \n"; m1.display(); cout << endl; cout << "矩阵对象m2: \n"; m2.display(); cout << endl; cout << "矩阵对象m3: \n"; m3.display(); cout << endl; } void test2() { Matrix m1(2, 3); m1.clear(); const Matrix m2(m1); m1.at(0, 0) = -999; cout << "m1.at(0, 0) = " << m1.at(0, 0) << endl; cout << "m2.at(0, 0) = " << m2.at(0, 0) << endl; cout << "矩阵对象m1第0行: "; output(m1, 0); cout << "矩阵对象m2第0行: "; output(m2, 0); } int main() { cout << "测试1: \n"; test1(); cout << "测试2: \n"; test2(); }
运行测试结果截图:
实验任务5
User.hpp
#include <iostream> #include <string> #include <iomanip> class User { private: std::string name; std::string password; std::string email; public: User(const std::string& name, const std::string& password = "123456", const std::string& email = "") : name(name), password(password), email(email) {} void set_email() { std::string input; std::cout << "Enter email address: "; while (true) { std::cin >> input; if (input.find('@') != std::string::npos) { email = input; std::cout << "email is set successfully...\n"; break; } else { std::cout << "illegal email. Please re-enter email:"; } } } void change_password() { const int max_attempts = 3; int attempts = 0; std::string old_password; std::cout << "Enter old password: "; while (attempts < max_attempts) { std::cin >> old_password; if (old_password == password) { std::string new_password; std::cout << "Enter new password: "; std::cin >> new_password; password = new_password; std::cout << "new password is set successfully...\n"; return; } else { attempts++; if(attempts != 3){ std::cout << "password input error. Please re-enter again:"; } } } std::cout << "password input error. Please try after a while\n"; } void display() const { std::cout << "name: " << name << "\n"; std::cout << "pass: "; for (char ch : password) { std::cout << '*'; } std::cout << "\n"; std::cout << "email: " << email << "\n"; } };
task5.cpp
#include "user.hpp" #include <iostream> #include <vector> #include <string> using std::cin; using std::cout; using std::endl; using std::vector; using std::string; void test() { vector<User> user_lst; User u1("Alice", "2024113", "Alice@hotmail.com"); user_lst.push_back(u1); cout << endl; User u2("Bob"); u2.set_email(); u2.change_password(); user_lst.push_back(u2); cout << endl; User u3("Hellen"); u3.set_email(); u3.change_password(); user_lst.push_back(u3); cout << endl; cout << "There are " << user_lst.size() << " users. they are: " << endl; for(auto &i: user_lst) { i.display(); cout << endl; } } int main() { test(); }
运行测试结果截图:
实验任务6
date.h
#pragma once
#include<iostream>
#include<cstdlib>
using namespace std;
class Date {
private:
int year;
int month;
int day;
int totalDays;
public:
Date(int year, int month, int day);
int getYear()const {
return year;
}
int getMonth()const {
return month;
}
int getDay()const {
return day;
}
int getMaxDay()const;
bool isLeapYear()const {
return year % 4 == 0 && year % 100 != 0 || year % 400 == 0;
}
void show() const;
int distance(const Date& date)const {
return totalDays - date.totalDays;
}
};
namespace {
const int DAYS_BEFIRE_MONTH[] = { 0,31,59,90,120,151,181,212,243,273,304 ,334,365 };
}
Date::Date(int year, int month, int day) :year(year), month(month), day(day) {
if (day <= 0 || day > getMaxDay()) {
cout << "Invalid date: ";
show();
cout << endl;
exit(1);
}
int years = year - 1;
totalDays = years * 365 + years / 4 - years / 100 + years / 400 + DAYS_BEFIRE_MONTH[month - 1] + day;
if (isLeapYear() && month > 2) totalDays++;
}
int Date::getMaxDay()const {
if (isLeapYear() &&month == 2)
return 29;
else return DAYS_BEFIRE_MONTH[month] - DAYS_BEFIRE_MONTH[month - 1];
}
void Date::show()const {
cout << getYear() << "-" << getMonth() << "-" << getDay();
}
account.hpp
#pragma once
#include"date.hpp"
#include<string>
#include<cmath>
#include<iostream>
using namespace std;
class SavingsAccount {
private:
string id;
double balance;
double rate;
Date lastDate;
double accumulation;
static double total;
void record(const Date& date, double amount, const string& desc);
void error(const string& msg) const;
double accumulate(const Date& date)const {
return accumulation + balance * date.distance(lastDate);
}
public:
SavingsAccount(const Date& date, const string& id, double rate);
const string& getId()const {
return id;
}
double getBalance()const {
return balance;
}
double getRate()const {
return rate;
}
static double getTotal() {
return total;
}
void deposit(const Date& date, double amount, const string& desc);
void withdraw(const Date& date, double amount, const string& desc);
void settle(const Date& date);
void show() const;
};
double SavingsAccount::total = 0;
SavingsAccount::SavingsAccount(const Date& date, const string& id, double rate) :
id(id), balance(0), rate(rate), lastDate(date), accumulation(0) {
date.show();
cout << "\t#" << id << "created" << endl;
}
void SavingsAccount::record(const Date& date, double amount, const string& desc) {
accumulation = accumulate(date);
lastDate = date;
amount = floor(amount * 100 + 0.5) / 100;
balance += amount;
total += amount;
date.show();
cout << "\t#" << id << "\t" << amount << "\t" << balance << "\t" << desc << endl;
}
void SavingsAccount::error(const string& msg) const {
cout << "Error(#" << id << "):" << msg << endl;
}
void SavingsAccount::deposit(const Date& date, double amount, const string& desc) {
record(date, amount, desc);
}
void SavingsAccount::withdraw(const Date& date, double amount, const string& desc) {
if (amount > getBalance())
error("not enough money");
else
record(date, -amount, desc);
}
void SavingsAccount::settle(const Date& date) {
double interest = accumulate(date) * rate / date.distance(Date(date.getYear() - 1, 1, 1));
if (interest != 0) record( date,interest,"interest" );
accumulation = 0;
}
void SavingsAccount::show()const {
cout << id << "\tBalance: " << balance;
}
task6.cpp
#include"account.hpp"
#include<iostream>
using namespace std;
int main() {
Date date { 2008,11,1 };
SavingsAccount accounts[] = {
SavingsAccount(date,"03755217",0.015),
SavingsAccount(date,"02342342",0.015)
};
const int n = sizeof(accounts) / sizeof(SavingsAccount);
accounts[0].deposit(Date(2008, 11, 5), 5000, "salary");
accounts[1].deposit(Date(2008, 11, 25), 10000, "sell stock 0323");
accounts[0].deposit(Date(2008, 12, 5), 5500, "salary");
accounts[1].withdraw(Date(2008, 12, 20), 4000, "buy a laptop");
cout << endl;
for (int i = 0; i < n; i++) {
accounts[i].settle(Date(2009, 1, 1));
accounts[i].show();
cout << endl;
}
cout << "Total: " << SavingsAccount::getTotal() << endl;
return 0;
}
运行测试结果截图: