java第五次作业
1.分别使用for循环，while循环，do循环求1到100之间所有能被3整除的整数的和。
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub int sum=0; for (int i=1;i<=100;i++) { if (i%3==0) { sum=sum+i; } } System.out.println(sum); } }
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub int i=1; int sum=0; while (i<100) { if (i%3==0) { sum=sum+i; } i++; } System.out.println(sum); } }
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub int i=1; int sum=0; do { if (i%3==0) { sum=sum+i; } i++; } while (i<=100); System.out.println(sum); } }
2.输出0-9之间的数，但是不包括5.
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub for (int i = 0; i < 10; i++) { if (i!=5) { System.out.println(i); } } } }
3.编写一个程序，求整数n的阶乘，例如5的阶乘是1*2*3*4*5
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input=new Scanner(System.in); System.out.println("请输入数字"); int a=input.nextInt(); int sum=1; for (int i = 1; i <=a; i++) { sum=sum*i; } System.out.println(sum); } }
4.编写一个程序，输入任意学生成绩,如果输入不合法(<0或者>100),提示输入错误,重新输入,直到输入合法程序结束
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input=new Scanner(System.in); System.out.println("请输入数字"); int a=input.nextInt(); if (a<0||a>100) { System.out.println("重新输入"); }else { System.out.println("输入合法"); } a=input.nextInt(); } }
5.假设某员工今年的年薪是30000元，年薪的年增长率6%。编写一个Java应用程序计算该员工10年后的年薪，并统计未来10年从(今年算起）总收入。
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub int i=1; double x=30000; double y=x; while (i <= 9){ x=x*1.06; y=y+x; i++; }System.out.println("十年后的年薪为"+x); System.out.println("这十年的总收入为"+y); } }
1.打印出所有的"水仙花数"，所谓"水仙花数"是指一个三位数，其各位数字立方和等于该数本身。例如：153是一个"水仙花数"，因为153=1的三次方＋5的三次方＋3的三次方。（知识点：循环语句、条件语句）
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub int i = 100; int d, b, c; for (i = 100; i < 1000; i++) { d = i / 100; b = i / 10 % 10; c = i % 10; if (d * d * d + b * b * b + c * c * c == i) { System.out.println(i); } } } }
2.输入年月日，判断这是这一年中的第几天（知识点：循环语句、条件语句）
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); System.out.println("输入年份"); int nian = input.nextInt(); System.out.println("输入月份"); int yue = input.nextInt(); System.out.println("输入日期"); int ri = input.nextInt(); if (nian % 400 == 0 || (nian % 4 == 0 && nian % 100 != 0)) { System.out.println("本年二月只有二十八天"); switch (yue) { case 1: System.out.println(ri); break; case 2: System.out.println(31 + ri); break; case 3: System.out.println(31 + 28 + ri); break; case 4: System.out.println(31 + 28 + 31 + ri); break; case 5: System.out.println(31 + 28 + 31 + 30 + ri); break; case 6: System.out.println(31 + 28 + 31 + 30 + 31 + ri); break; case 7: System.out.println(31 + 28 + 31 + 30 + 31 + 30 + ri); break; case 8: System.out.println(31 + 28 + 31 + 30 + 31 + 30 + 31 + ri); break; case 9: System.out.println(31 + 28 + 31 + 30 + 31 + 30 + 31 + ri); break; case 10: System.out.println(31 + 28 + 31 + 30 + 31 + 30 + 31 + 30 + ri); break; case 11: System.out.println(31 + 28 + 31 + 30 + 31 + 30 + 31 + 30 + 31 + ri); break; case 12: System.out.println(31 + 28 + 31 + 30 + 31 + 30 + 31 + 30 + 31 + 30 + ri); break; } } else { System.out.println("本年二月只有二十九天"); switch (yue) { case 1: System.out.println(ri); break; case 2: System.out.println(31 + ri); break; case 3: System.out.println(31 + 29 + ri); break; case 4: System.out.println(31 + 29 + 31 + ri); break; case 5: System.out.println(31 + 29 + 31 + 30 + ri); break; case 6: System.out.println(31 + 29 + 31 + 30 + 31 + ri); break; case 7: System.out.println(31 + 29 + 31 + 30 + 31 + 30 + ri); break; case 8: System.out.println(31 + 29 + 31 + 30 + 31 + 30 + 31 + ri); break; case 9: System.out.println(31 + 29 + 31 + 30 + 31 + 30 + 31 + ri); break; case 10: System.out.println(31 + 29 + 31 + 30 + 31 + 30 + 31 + 30 + ri); break; case 11: System.out.println(31 + 29 + 31 + 30 + 31 + 30 + 31 + 30 + 31 + ri); break; case 12: System.out.println(31 + 29 + 31 + 30 + 31 + 30 + 31 + 30 + 31 + 30 + ri); break; } } } }
3.由控制台输入一个4位整数，求将该数反转以后的数，如原数为1234，反转后的数位4321（知识点：循环语句、条件语句）
package com; import java.util.Scanner; public class Test5 { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); System.out.println("输入一个四位整数"); int a = input.nextInt(); int b, c, d, e; if (a < 1000 || a > 10000) { System.out.println("输入的数不合法"); } else { b = a / 1000; c = a % 1000 / 100; d = a % 100 / 10; e = a % 10; System.out.println(e * 1000 + d * 100 + c * 10 + b); } } }
posted on 2021-04-06 16:23 HumbleSwag 阅读(40) 评论(0) 编辑 收藏 举报
