雪溯

摘要： 问题 G: a interesting game时间限制:1 Sec内存限制:128 MB提交:29解决:10[提交][状态][讨论版]题目描述Oneday,Kidisinclass.ButKidthinkwhattheteacherteachingissoboring,sohedecidetopl... 阅读全文

摘要： Challenge of WisdomTime Limit:2 Seconds Memory Limit:32768 KBBackground"Then, I want to know whether you're a wise boy!"Problem"I have a great deal of... 阅读全文

摘要： 5152. Brute-force Algorithm EXTREMEProblem code: BFALGPlease clickhereto download a PDF version of the contest problems. The problem is problem B in t... 阅读全文

摘要： #include #include #include #include #include #include #include using namespace std;class insertSort{public: insertSort(int * a,int size){ th... 阅读全文

摘要： 7.1 int[][] triArray{ {1}, {1,2}, {1,2,3},};7.2 array[2].length8.1 Unified Modeling Language:UMLUML class diagramCircle_____________radius:double_____... 阅读全文

摘要： 第六章 一维数组1数组初始化语法 array initializer2for each loop3off-by-one error 通常是在循环中该使用<的地方使用了<=4复制数组:1.for 2.System.arraycopy 3.clone5arraycopy(sourceArray, src... 阅读全文

摘要： 1.method header: modifier, return value type, method signature(method name, parameter)method body2.value-returning methodvoid methodmethod overloading... 阅读全文

摘要： 1 think before codingcode incrementally2sentinel valuesentinel-controlled loop3 输入输出重定向 > = 1;i--){ sum += 1d/i; }System.out.println(sum);//11.3970039... 阅读全文

摘要： 1单向if语句双向if语句dangling elseswitch:char,byte,short,int2javax.swing.JOptionPane.showConfirmDialog(null,text);返回值:JOptionPane.YES_OPTION:0JOptionPane.NO_O... 阅读全文

摘要： 1原始数据类型(primitive data type) == 基本类型 (fundamental type)byte short int long float double char boolean引用类型 reference type2System.in System.outjava.util.... 阅读全文