02 2023 档案
摘要：Q1 题目描述： 代码实现： 1 def coords(fn, seq, lower, upper): 2 """ 3 >>> seq = [-4, -2, 0, 1, 3] 4 >>> fn = lambda x: x**2 5 >>> coords(fn, seq, 1, 9) 6 [[-2,
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摘要：一：例题 例题1： 题目描述： #递归算法def g(n): """Return the value of G(n), computed recursively. >>> g(1) 1 >>> g(2) 2 >>> g(3) 3 >>> g(4) 10 >>> g(5) 22 >>> from co
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摘要：1 def cond(): 2 "*** YOUR CODE HERE ***" 3 return False 4 5 def true_func(): 6 "*** YOUR CODE HERE ***" 7 print(42) 8 9 10 def false_func(): 11 "*** Y
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摘要：题目描述： 代码： 1 def num_eights(x): 2 """Returns the number of times 8 appears as a digit of x. 3 4 >>> num_eights(3) 5 0 6 >>> num_eights(8) 7 1 8 >>> num
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摘要：题目描述： A guest at a party is a celebrity if this person is known by every other guest, but knows none of them. There is at most one celebrity at a part
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摘要：1 def cycle(f1, f2, f3): 2 """Returns a function that is itself a higher-order function. 3 4 >>> def add1(x): 5 ... return x + 1 6 >>> def times2(x):
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