用js实现跳转页面的方法

<span id="tiao">3</span><a href="javascript:countDown"></a>布丁足迹;秒后自动跳转……<meta http-equiv=refresh content=3;url='/search/billsearch.jsp'</ul>

<!--脚本开始-->
<script language="javascript" type="">
function countDown(secs){
  tiao.innerText=secs;
  if(--secs>0)
   setTimeout("countDown("+secs+")",1000);
  }
  countDown(3);
</script>
<!--脚本结束-->
 

  按钮式:

  <INPUT name="pclog" type="button" value="GO" onClick="location.href='http://www.ddhbb.com/'">

  链接式:

  <a href="javascript:history.go(-1)">返回上一步</a>

  <a href="<%=Request.ServerVariables("HTTP_REFERER")%>">返回上一步</a>

  直接跳转式:

  <script>window.location.href='http://www.ddhbb.com';</script>

  开新窗口:

  <a href="javascript:" onClick="window.open('http://www.ddhbb.com/blog /guestbook.asp','','height=500,width=611,scrollbars=yes,status=yes')"& gt;布丁          足迹</a>

  JS跳转页面参考代码
第一种:
<script language="javascript" type="text/javascript">
window.location.href="login.jsp?backurl="+window.location.href;
</script>
第二种:
<script language="javascript">
alert("返回");
window.history.back(-1);
</script>
第三种:
<script language="javascript">
window.navigate("top.jsp");
</script>
第四种:
<script language="JavaScript">
self.location=’top.htm’;
</script>
第五种:
<script language="javascript">
alert("非法访问!");
top.location=’xx.jsp’;
</script>

=====javascript中弹出选择框跳转到其他页面=====
<script language="javascript">
<!--
function logout()...{
if (confirm("你确定要注销身份吗?是-选择确定,否-选择取消"))...{
window.location.href="logout.asp?act=logout"
}
}
-->
</script>
 

====javascript中弹出提示框跳转到其他页面=====
<script language="javascript">
<!--
function logout()...{
alert("你确定要注销身份吗?");
window.location.href="logout.asp?act=logout"
}
-->
</script>

posted on 2015-09-14 22:12  薛理想  阅读(1876)  评论(0编辑  收藏  举报