Java 面试题分析
分析代码如下:
demo1:
public static void main(String[] args) { String str1 = "abc";//常量池 String str2 = "abc";//常量池 String str3 = new String("abc");//堆 中 System.out.println(str1 == str2);//同一个直 true System.out.println(str1 == str3);//不同 false System.out.println(str1.equals(str3));//Hashcode 相同 System.out.println(str2.equals(str3));//Hashcode 相同 System.out.println(); Integer i =127,j=127,m=129,n=129; System.out.println(i==j);// System.out.println(m==n); }
结果:
true false true true true false
Integer 原码如下:
assert IntegerCache.high >= 127;
/** * Returns an {@code Integer} instance representing the specified * {@code int} value. If a new {@code Integer} instance is not * required, this method should generally be used in preference to * the constructor {@link #Integer(int)}, as this method is likely * to yield significantly better space and time performance by * caching frequently requested values. * * This method will always cache values in the range -128 to 127, * inclusive, and may cache other values outside of this range. * * @param i an {@code int} value. * @return an {@code Integer} instance representing {@code i}. * @since 1.5 */ public static Integer valueOf(int i) { assert IntegerCache.high >= 127; if (i >= IntegerCache.low && i <= IntegerCache.high) return IntegerCache.cache[i + (-IntegerCache.low)]; return new Integer(i); }
demo2;
public class NULL { public static void test() { System.out.println("test"); } public static void main(String[] args) { ((NULL) null).test();//同 NULL.test(); NULL n = new NULL(); n.test(); //NULL.test(); Object obj = 0.6324; System.out.println(obj.getClass());//Double final StringBuffer a = new StringBuffer("aaa"); a.append("a");//special System.out.println(a); } }