怎样将包含元组的列表转换为字典？

原始数据   [('firstid', '1'), ('language', 'g'), ('lastid', '199'), ('sale', '759'), ('saledate', '16. Mai 2018'), ('section', 'Moderne Kunst'), ('action', 'Browse')]

转换结果是： 

{'language': '[1,g]', 'section': 'Moderne Kunst', 'sale': '[759,16. Mai 2018]', 'saledate': '16. Mai 2018', 'action': 'Browse', 'lastid': '199'}

 解决  别人提问的问题，问题网页是：   https://segmentfault.com/q/1010000000161056

 

代码：

 

requests_list = [('language', '1'), ('language', 'g'), ('lastid', '199'), ('sale', '759'), ('saledate', '16. Mai 2018'),
 ('section', 'Moderne Kunst'), ('action', 'Browse')]

key_list = []
for ii in requests_list:
    key = ii[0]
    key_list.append(key)

key_list = list(set(key_list))
print key_list

req_dict = {}
req_dict_list = []
for kk in key_list:
    kk_list = []
    for mm in requests_list:
        if kk in str(mm):
            kk_list.append(mm[1])
    print len(kk_list)
    print (kk_list)
    if len(kk_list)>=2:
        kk_list_str = ','.join(kk_list)
        kk_list_str = "[" + kk_list_str + "]"
    else:
        kk_list_str = kk_list[0]

    req_dict_list.append(kk_list_str)
print req_dict_list
print kk

print dict(zip(key_list,req_dict_list))