题解:

先把询问排序

然后根据单调性来做

代码:

#include<bits/stdc++.h>
using namespace std;
int n,m,a[50005],b[50005],f[50005],ans[50005];
int cmp(int x,int y)
{
    return b[x]<b[y];
}
int main()
{
    scanf("%d%d",&n,&m);
    int num=0,j=1;
    for (int i=1;i<=n;i++)scanf("%d",&a[i]);
    for (int i=1;i<=m;i++)scanf("%d",&b[i]),f[i]=i;
    sort(f+1,f+m+1,cmp);
    for (int i=1;i<=m;i++)
     {
        while (a[j]+num<=b[f[i]])num+=a[j],j++;
        ans[f[i]]=j;
     }
    for (int i=1;i<=m;i++)printf("%d\n",ans[i]); 
}

 

posted on 2018-03-17 13:47  宣毅鸣  阅读(82)  评论(0编辑  收藏  举报