[LC] 82. Remove Duplicates from Sorted List II
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
Example 1:
Input: 1->2->3->3->4->4->5 Output: 1->2->5
Example 2:
Input: 1->1->1->2->3 Output: 2->3
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution { public ListNode deleteDuplicates(ListNode head) { if (head == null || head.next == null) { return head; } ListNode dummy = new ListNode(-1); dummy.next = head; ListNode cur = dummy; // check the next two node while(cur.next != null && cur.next.next != null) { if (cur.next.val == cur.next.next.val) { int num = cur.next.val; while(cur.next != null && cur.next.val == num) { cur.next = cur.next.next; } } else { cur = cur.next; } } return dummy.next; } }
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