北邮机试——huffman权值问题

我的Online Judge账号还没有这道题的访问权限(1172),这让我情何以堪,好在还是找到了题目,题目想做的比较好还是需要一些功底的。

做一下,马上就复试了,注释也没时间写,代码能看清楚:

  1 /*
  2  * author: xuangong
  3  * time: 2013-4-9 21:42
  4  */
  5 #include <stdio.h>
  6 #include <stdlib.h>
  7 
  8 typedef struct _huffmannode
  9 {
 10     int data;
 11     struct _huffmannode *lchild;
 12     struct _huffmannode *rchild;
 13 }huffmannode, *phuffmannode;
 14 
 15 typedef struct _list
 16 {
 17     phuffmannode node;
 18     struct _list * next;
 19 }list, *plist;
 20 
 21 plist init_list()
 22 {
 23     plist head = (plist)malloc(sizeof(struct _list));
 24     head->next = head->node = NULL;
 25     return head;
 26 }
 27 
 28 void add_list(plist head, phuffmannode node)
 29 {
 30     plist insert = (plist)malloc(sizeof(struct _list));
 31     insert->node = node;
 32     insert->next = NULL;
 33     if(head==NULL)
 34         printf("head is null\n");
 35     if(head!=NULL)
 36     {
 37         plist pre = head;
 38         head = head->next;
 39         while(head!=NULL && node->data > head->node->data)
 40         {
 41             pre = head;
 42             head = head->next;
 43         }
 44         insert->next = pre->next;
 45         pre->next = insert;
 46     }
 47 }
 48 
 49 void display(plist head)
 50 {
 51     head = head->next;
 52     while(head!=NULL)
 53     {
 54         printf("%d ", head->node->data);
 55         head = head->next;
 56     }
 57     printf("\n");
 58 }
 59 
 60 phuffmannode get_list(plist head)
 61 {
 62     plist temp = head->next;
 63     phuffmannode top = head->next->node;
 64     head->next = head->next->next;
 65     free(temp);
 66     return top;
 67 }
 68 
 69 phuffmannode create_huffmannode(plist li)
 70 {
 71     phuffmannode lchild, rchild, node;
 72     if(li->next!=NULL && li->next->next == NULL)
 73         return get_list(li);
 74     while(li->next!=NULL && li->next->next!=NULL)
 75     {
 76         lchild = get_list(li);
 77         rchild = get_list(li);
 78         node = (phuffmannode)malloc(sizeof(struct _huffmannode));
 79         node->data = lchild->data + rchild->data;
 80         node->lchild  = lchild;
 81         node->rchild = rchild;
 82         add_list(li, node);
 83     }
 84     return get_list(li);
 85 }
 86 
 87 int traversetree(phuffmannode root, int level)
 88 {
 89     if(root==NULL)
 90         return 0;
 91     if(root->lchild==NULL && root->rchild==NULL)
 92         return root->data*level;
 93     return traversetree(root->lchild ,level+1) + traversetree(root->rchild, level+1);
 94 }
 95 
 96 void destorytree(phuffmannode root)
 97 {
 98     if(root==NULL)
 99         return;
100     if(root->lchild==NULL && root->rchild==NULL)
101     {
102         free(root);
103         root = NULL;
104         return;
105     }
106     destorytree(root->lchild);
107     destorytree(root->rchild);
108 }
109 
110 int main()
111 {
112     int count, i, data, level;
113     phuffmannode node;
114     level = 0;
115     plist head = init_list();
116     while(scanf("%d", &count)!=EOF)
117     {
118         for(i=0;i<count;i++)
119         {
120             scanf("%d", &data);
121             node = (phuffmannode)malloc(sizeof(struct _huffmannode));
122             node->data = data;
123             node->lchild = node->rchild = NULL;
124             add_list(head, node);
125         }
126         phuffmannode root = create_huffmannode(head);
127         printf("This huffman tree is value is:%d\n", traversetree(root, level));
128         destorytree(root);
129     }
130     return 0;
131 }

 上面是链表建树的办法,如果不建树,不用链表,仅仅为了完成这道题,今天看的方法真是帅呆了!

View Code
 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 
 4 int val[1001];
 5 
 6 int cmp(const void * a,const void * b) //when the result is true "a>b" , a is after b
 7 {
 8     return *(int *)a - *(int *)b;
 9 }
10 
11 int main()
12 {
13     int n;
14     int i;
15     int ans;
16     while(scanf("%d",&n) != EOF)
17     {
18         ans = 0;
19         for(i = 0;i < n;i++) 
20             scanf("%d",&val[i]);
21         for(i = 1;i < n;i++)
22         {
23             qsort(&val[i - 1], n - i + 1, sizeof(val[0]), cmp);
24             ans += val[i - 1] + val[i];
25             val[i] += val[i - 1];
26         }
27         printf("%d\n",ans);
28     }
29     return 0;
30 }

 

 

 

posted on 2013-04-09 22:04  xuangong  阅读(213)  评论(0编辑  收藏  举报

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