摘要: 1 vector::iterator result = find( L.begin( ), L.end( ), 1 ); //查找1 2 if ( result == L.end( ) ) //没找到 3 cout << "No" << endl; 4 else //找到 5 cout << "Yes" << endl; 6 7 } 阅读全文
posted @ 2016-07-18 17:14 hellohyi 阅读(25527) 评论(0) 推荐(0) 编辑