摘要: #pragma comment(linker, "/STACK:102400000,102400000")#include#include#include#includeusing namespace std;const int N=1024;const int inf=1edges... 阅读全文
posted @ 2015-08-13 19:20 xryz 阅读(140) 评论(0) 推荐(0) 编辑
摘要: #include #include #include #include #include #include using namespace std;int gcd(int u,int v){ if(u10*180) difms=10*360-difms; if(d... 阅读全文
posted @ 2015-08-13 17:13 xryz 阅读(115) 评论(0) 推荐(0) 编辑
摘要: 题目关键是建模,之后就是简单地增广路。#include#include#include#include#includeusing namespace std;const int N=1024;const int inf=1q;void ford(){ int a[N],vis[... 阅读全文
posted @ 2015-08-13 10:52 xryz 阅读(102) 评论(0) 推荐(0) 编辑