20165321 实验三 敏捷开发与XP实践-4
2018-04-27 20:24 Ze6Pui3Loeng4 阅读(121) 评论(0) 编辑 收藏 举报Java密码学程序
import java.util.*;
public class Lfsr {
public static void main(String[] args) {
System.out.println("请输入移位寄存器的级数n:");
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
System.out.println("请设置初态:");
int[] a = new int[n];//状态数
int sum=1;
for (int i = 0; i < n; i++) {
a[i] = sc.nextInt();
sum=2*sum;
}
System.out.println("请输入结构常数:");//形如[c1,c2,c3,c4,c5]
int[] c = new int[n];//存储的为反馈函数,与反馈函数的对应规律为:若结构常数为[0,1,0,1],则反馈函数为
for (int i = n-1; i >= 0; i--) {
c[i] = sc.nextInt();
}
System.out.println("线性移位寄存器输出序列为:");
for (int i = 0; i <sum-1; i++) {
System.out.printf("%d", a[0]);
operate1(a, c, n);
}
System.out.println(" ");
System.out.println("对偶移位寄存器输出序列为:");
for(int i=0;i<sum-1;i++) {
System.out.printf("%d",a[0]);
operate2(a,c,n);
}
}
private static int[] operate2(int[] a, int[] c, int n) {
int temp=a[0];
for(int i=0;i<n-1;i++) {
a[i]=a[i+1];
}
a[n-1]=0;
if(temp==1) {
for(int j=0;j<n;j++) {
a[j]=(a[j]+c[n-j-1])%2;
}
}
return a;
}
private static int[] operate1(int[] a, int[] c, int n) {
int temp=0;
for (int i = 0; i < n; i++) {
if (a[i] * c[i] == 1) {
temp += 1;
}
}
a[n - 1] %= 2;
for (int j = 0; j < n - 1; j++) {
a[j] = a[j + 1];
}
a[n-1]=temp;
return a;
}
}
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