C语言:编程求任意月份的天数
闰年问题,因为二月份的天数与闰年有关。闰年的判断依据是:若某年能被4整除,但不能被100整除,则这一年是闰年;若某年能被400整除,则这一年也是闰年
#include <stdio.h> #include <stdlib.h> main(){ int year, month, days; while (1) { printf("输入年份:"); scanf("%d",&year); if (year==9999) break; printf("输入月份:"); scanf("%d", &month); switch(month){ case 1: case 3: case 5: case 7: case 8: case 10: case 12: days=31; break; case 4: case 6: case 9: case 11: days=30; break; case 2: // 判断闰年 if(year%4==0 && year%100!=0 || year%400==0) days=29; else days=28; break; default: printf("月份输入错误!\n"); exit(1); break; } printf("天数:%d\n", days); } }
改进1:bz为1时表示月份输入错误,不用输出天数
#include <stdio.h> #include <stdlib.h> main(){ int year, month, days,bz; while (1) { bz=0; printf("输入年份:"); scanf("%d",&year); if (year==9999) //break; exit(1); printf("输入月份:"); scanf("%d", &month); switch(month){ case 1: case 3: case 5: case 7: case 8: case 10: case 12: days=31; break; case 4: case 6: case 9: case 11: days=30; break; case 2: // 判断闰年 if(year%4==0 && year%100!=0 || year%400==0) days=29; else days=28; break; default: printf("月份输入错误!\n"); bz=1; //exit(1); break; } if (bz==0) printf("天数:%d\n", days); } }