Codeforces 812 A Sagheer and Crossroads

题目链接：http://codeforces.com/contest/812/problem/A

题意：其实就是判断行人通过时，该路上有没有汽车通过，用常识去写就好了，输入的其实分别是4条路向左向右向前以及行人的是否可以通行的信号，判断是否会发生事故

 1 #include <iostream>
 2 #include <cstring>
 3 #include <string>
 4 #include <vector>
 5 #include <queue>
 6 #include <map>
 7 #include <set>
 8 #include <algorithm>
 9 #define N 110
10 #define inf 0x3f3f3f3f
11 #define LL long long
12 using namespace std;
13 int l[4], s[4], r[4], p[4];
14 int main() {
15     cin.sync_with_stdio(false);
16     int flag = 0;
17     for (int i = 0; i < 4; i++) {
18         cin >> l[i] >> s[i] >> r[i] >> p[i];
19         if (p[i] == 1) {
20             if (l[i] == 1 || s[i] == 1 || r[i] == 1) {
21                 cout << "YES" << endl;
22                 return 0;
23             }
24         }
25     }
26     for (int i = 0; i < 4; i++) {
27         if (r[i] == 1 && p[(i + 1) % 4] == 1) {
28             cout << "YES" << endl;
29             return 0;
30         }
31     }
32     for (int i = 0; i < 4; i++) {
33         if (s[i] == 1 && p[(i + 2) % 4] == 1) {
34             cout << "YES" << endl;
35             return 0;
36         }
37     }
38     for (int i = 0; i < 4; i++) {
39         if (l[i] == 1 && p[(i + 3) % 4] == 1) {
40             cout << "YES" << endl;
41             return 0;
42         }
43     }
44     cout << "NO" << endl;
45     return 0;
46 }

2017-06-02 09:09:19

posted @ 2017-06-02 09:10  ガ落涙『不變』  阅读(76)  评论(0)  编辑  收藏  举报