摘要: select a.id,a.`name` AS '姓名',b.`subject`,c.`achievement` from aaa AS a left join ccc AS c on a.id=c.uid left join bbb AS b on c.sid=b.id where a.id in(1,2,3) group by c.achievement having c.achievem... 阅读全文
posted @ 2016-07-16 22:54 偏执Dog 阅读(4848) 评论(0) 推荐(0) 编辑