bzoj 4034: [HAOI2015]T2

树刨 一定要注意long long

  1 #include<cstdio>
  2 #include<iostream>
  3 #include<cstring>
  4 #include<cstdlib>
  5 #include<cmath>
  6 #include<queue>
  7 #include<algorithm>
  8 #include<vector>
  9 #define M 2000009
 10 #define EPS 1e-10
 11 #define MO 10000
 12 #define ll long long
 13 using namespace std;
 14 ll read()
 15 {
 16     char ch=getchar();
 17     ll x=0,f=1;
 18     for(;ch<'0'||ch>'9';ch=getchar())
 19         if(ch=='-')
 20           f=-1;
 21     for(;ch>='0'&&ch<='9';ch=getchar())
 22         x=x*10+ch-'0';
 23     return x*f;
 24 }
 25 int cnt,head[M],next[M],u[M],n,m,a[M],R[M],size[M],lian[M],dui[M],T,b[M],fa[M];
 26 struct data
 27 {
 28   ll he,lazy;
 29 }shu[M];
 30 void jiaa(int a1,int a2)
 31 {
 32   cnt++;
 33   next[cnt]=head[a1];
 34   head[a1]=cnt;
 35   u[cnt]=a2;
 36 }
 37 void dfs(int x)
 38 {
 39   size[x]=1;
 40   for(int i=head[x];i;i=next[i])
 41     if(u[i]!=fa[x])
 42       {
 43          
 44         fa[u[i]]=x;
 45         dfs(u[i]);
 46         size[x]+=size[u[i]];
 47       }
 48 }
 49 void dfs1(int x,int gen)
 50 {
 51   R[x]=dui[x]=++T;
 52   b[dui[x]]=a[x];
 53   lian[x]=gen;
 54   int k=0;
 55   for(int i=head[x];i;i=next[i])
 56     if(u[i]!=fa[x]&&size[u[i]]>size[k])
 57       k=u[i];
 58   if(!k)
 59     return;
 60   dfs1(k,gen);
 61   for(int i=head[x];i;i=next[i])
 62     if(u[i]!=fa[x]&&u[i]!=k)
 63       dfs1(u[i],u[i]);
 64   R[x]=T;
 65 } 
 66 void xia(int x,int l,int r)
 67 {
 68   int mid=(l+r)>>1;
 69   ll q=shu[x].lazy;
 70   shu[x].lazy=0;
 71   shu[x*2].he+=(ll)q*(mid-l+1);
 72   shu[x*2+1].he+=(ll)q*(r-mid);
 73   shu[x*2].lazy+=q;
 74   shu[x*2+1].lazy+=q; 
 75 }
 76 void jia(int x,int l,int r,int L,int R,int q)
 77 {
 78   if(l>=L&&r<=R)
 79     {
 80       shu[x].he+=(ll)q*(r-l+1);
 81       shu[x].lazy+=q;
 82       return;
 83     }
 84   int mid=(l+r)>>1;
 85   if(shu[x].lazy)
 86     xia(x,l,r);
 87   if(L<=mid)
 88     jia(x*2,l,mid,L,R,q);
 89   if(R>mid)
 90     jia(x*2+1,mid+1,r,L,R,q);
 91   shu[x].he=shu[x*2].he+shu[x*2+1].he;
 92 }
 93 ll xxun(int x,int l,int r,int L,int R)
 94 {
 95   if(l>=L&&r<=R)
 96     return shu[x].he;
 97   int mid=(l+r)>>1;
 98   ll sum=0;
 99   if(shu[x].lazy)
100     xia(x,l,r);
101   if(L<=mid)
102     sum+=xxun(x*2,l,mid,L,R);
103   if(R>mid)
104     sum+=xxun(x*2+1,mid+1,r,L,R);
105   shu[x].he=shu[x*2].he+shu[x*2+1].he;  
106   return sum;
107 }
108 ll xun(int x)
109 {
110   ll sum=0;
111   for(;x;x=fa[lian[x]])
112     sum+=xxun(1,1,n,dui[lian[x]],dui[x]);
113   return sum;
114 }
115 int main()
116 {
117    n=read();
118    m=read();
119    for(int i=1;i<=n;i++)
120      a[i]=read();
121    for(int i=1;i<n;i++)
122      {
123        int a1=read(),a2=read();
124        jiaa(a1,a2);
125        jiaa(a2,a1);
126      }
127    dfs(1);
128    dfs1(1,1);
129    for(int i=1;i<=n;i++)
130    jia(1,1,n,dui[i],dui[i],a[i]);
131    for(int i=1;i<=m;i++)
132      {
133        int a1=read(),x=read(),a;
134        if(a1!=3)
135          a=read();
136        if(a1==1)
137          jia(1,1,n,dui[x],dui[x],a);
138        if(a1==2)
139          jia(1,1,n,dui[x],R[x],a);
140        if(a1==3)
141          printf("%lld\n",xun(x));
142      }
143    return 0;
144 }

 

posted @ 2016-07-08 21:50  xiw5  阅读(112)  评论(0)  编辑  收藏  举报