reverse-integer
Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321
//翻转数字 注意点:1.如果数字的最后后几位是0 eg10,100; 2.数字如果溢出如何处理?
class Solution { public: int reverse(int x) { int IntMax = INT_MAX; int IntMin = INT_MIN; bool flag = false; int sum = 0; if(x<0) { x = abs(x); flag = true; } while(x){ int tmp = x%10; sum = sum*10+tmp; if(sum > INT_MAX){ if(flag = true) sum = INT_MIN; else sum = INT_MAX; } x = x/10; } if(flag){ sum *= -1; } return sum; } };