leetcode 83: Wildcard Matching

Wildcard MatchingMar 16 '12

Implement wildcard pattern matching with support for '?' and '*'.

'?' Matches any single character.
'*' Matches any sequence of characters (including the empty sequence).

The matching should cover the entire input string (not partial).

The function prototype should be:
bool isMatch(const char *s, const char *p)

Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "*") → true
isMatch("aa", "a*") → true
isMatch("ab", "?*") → true
isMatch("aab", "c*a*b") → false

 

 

uncompleted

public class Solution {     public boolean isMatch(String s, String p) {         // Start typing your Java solution below         // DO NOT write main() function         if(p.length() == 0) return s.length()==0 ? true : false;                 int i=0;         char c;         while(i<p.length() && i<s.length() && (c=p.charAt(i)) != '*') {             if( c!='?' && c!=s.charAt(i) ) return false;             i++;         }                 int j=s.length()-1;         int k=p.length()-1;                 while( j>=i && k>=i && (c=p.charAt(k)) != '*') {             if( c!='?' && c!=s.charAt(j) ) return false;             --j;             --k;         }                 if(i>j)return false;         else s=s.substring(i,j+1);         if(i>k) return false;         else p=p.substring(i,k+1);                 String[] pattern = p.split("[*]");         for(String temp:pattern){             if(temp.length()>0){                 int index = getFirstIndex(s,temp);                 if(index<0)                     return false;                 else                     s=s.substring(index+temp.length());             }            }           return true;     }         public int getFirstIndex(String s, String p){         if(s.length()<p.length()) return -1;         int i=0;         while(i<=s.length()-p.length()){             while(i<s.length() && p.charAt(0)!='?' && p.charAt(0)!=s.charAt(i))                 i++;             if(s.length()-i<p.length()) return -1;                         int j=i;             while(j-i<p.length() && (p.charAt(j-i)=='?'||p.charAt(j-i)==s.charAt(j)))                 j++;             if(j-i==p.length()) return i;             i++;         }         return -1;     } }


 

 

posted @ 2013-02-21 04:59  西施豆腐渣  阅读(216)  评论(0编辑  收藏  举报