leetcode 76: Reverse Linked List II
Reverse Linked List IIJun
27 '12
Reverse a linked list from position m to n. Do it in-place and in one-pass.
For example:
Given 1->2->3->4->5->NULL
, m =
2 and n = 4,
return 1->4->3->2->5->NULL
.
Note:
Given m, n satisfy
the following condition:
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { public ListNode reverseBetween(ListNode head, int m, int n) { // Start typing your Java solution below // DO NOT write main() function if( head==null | m==n) return head; ListNode start = new ListNode(0); start.next = head; head = start; n=n-m+1; while(--m>0 && start!=null) start = start.next; if(start==null) return head.next; ListNode cur = start.next; ListNode pre = null; ListNode nxt = null; while(cur!=null && n-->0) { nxt = cur.next; cur.next = pre; pre = cur; cur = nxt; } start.next.next = cur; ListNode t = start.next; start.next = pre; start = t; return head.next; } }