Java进制转换
其他转10进制
System.out.println(Integer.parseInt("10", 2));// bin System.out.println(Integer.parseInt("12", 3)); System.out.println(Integer.parseInt("742", 8));// oct System.out.println(Integer.parseInt("12A", 16));// hex
10进制转2,8,16
System.out.println(Integer.toBinaryString(255)); System.out.println(Integer.toHexString(255)); System.out.println(Integer.toOctalString(255));
jdk代码实现。
final static char[] digits = { '0' , '1' , '2' , '3' , '4' , '5' , '6' , '7' , '8' , '9' , 'a' , 'b' , 'c' , 'd' , 'e' , 'f' , 'g' , 'h' , 'i' , 'j' , 'k' , 'l' , 'm' , 'n' , 'o' , 'p' , 'q' , 'r' , 's' , 't' , 'u' , 'v' , 'w' , 'x' , 'y' , 'z' }; public static String toHexString(int i) { return toUnsignedString(i, 4); } public static String toOctalString(int i) { return toUnsignedString(i, 3); } public static String toBinaryString(int i) { return toUnsignedString(i, 1); } private static String toUnsignedString(int i, int shift) { char[] buf = new char[32]; int charPos = 32; int radix = 1 << shift; int mask = radix - 1; do { buf[--charPos] = digits[i & mask]; i >>>= shift; } while (i != 0); return new String(buf, charPos, (32 - charPos)); }