Layui 获取树全部选中的节点ID

话不多说直接上代码

        //监听授权按钮
        form.on('submit(Authorization)', function (data) {
            var userid = document.getElementById("UserId").value;
            var checkedData = tree.getChecked('ActorTreeid'); //获取选中节点的数据
            var nodeIds = new Array();
            nodeIds = getCheckedId(checkedData);
            var ActorTreeid = nodeIds;//JSON.stringify(nodeIds)
            $.ajax({
                type: 'POST',
                url: '../handler/User_Actor.ashx',
                data: { "userid": userid, "ActorTreeid": ActorTreeid },
                success: function (date) {
                    var result = date;
                    if (result == "1" || result == "2") {
                        layer.msg("授权成功!", {
                            icon: 6
                        });
                    } else
                    {
                        layer.msg("授权失败!" + result, {
                            icon: 5
                        });
                    }
                },
                dataType: "json",
                error: function (err) {
                    layer.msg("授权失败!" + err, {
                        icon: 5
                    });
                }
            });

            return false;
        });
        //获取所有选中的节点id
        function getCheckedId(data) {
            var id = "";
            $.each(data, function (index, item) {
                if (id != "") {
                    id = id + "$" + item.id;
                }
                else {
                    id = item.id;
                }
                //item 没有children属性
                if (item.children != null) {
                    var i = getCheckedId(item.children);
                    if (i != "") {
                        id = id + "$" + i;
                    }
                }
            });
            return id;
        }

 

posted @ 2020-09-06 14:14  幸运(● ̄(エ) ̄●)  阅读(1314)  评论(0编辑  收藏  举报
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