摘要: try lJson := TJsonObject.Create; lJson.S['wechatlinkname'] := self.WeChatLinkName; lJson.S['language'] := language; lJson.I['dept_id'] := dept_id; try 阅读全文
posted @ 2021-05-24 15:10 熊大熊二 阅读(398) 评论(0) 推荐(0) 编辑