委托的异步执行
public delegate int mydelegate(int x, int y); class Program { static void Main(string[] args) { Console.WriteLine("Main中正在执行的线程ID:{0}",Thread.CurrentThread.ManagedThreadId); ///实例化一个委托 mydelegate d = new mydelegate(Add); //委托的同步调用 //int resuit = d.Invoke(2, 4); //Console.WriteLine("2+4 is={0}",resuit); ///委托的异步调用 ///生成BeginInvoke的方法是 public IAsyncResult BeginInvoke(int x,int y,AsyncCallBack cb,Object state) ///生成EndInvoke的方法是 public int EndInvoke(IAsyncResult result) ///BeginInvoke和EndInvoke是一种耦合机制,EndInvoke需要一个IAsyncResult类型参数,BeginInvoke返回的是IAsyncResult //IAsyncResult IResuit = d.BeginInvoke(2, 3, null, null); //int AsyncResuit = d.EndInvoke(IResuit); //Console.WriteLine("2+4 is={0}",AsyncResuit); ///同步调用线程 /// //IAsyncResult IResuit = d.BeginInvoke(2, 4, null, null); //while (!IResuit.IsCompleted) //{ // Console.WriteLine("Doing more work in Main()"); // Thread.Sleep(1000); //} //int AsyncResuit = d.EndInvoke(IResuit); //Console.WriteLine("2+4 is={0}", AsyncResuit); //IAsyncResult IResuit = d.BeginInvoke(2, 4, null, null); //while (IResuit.AsyncWaitHandle.WaitOne(1000, true)) //{ // Console.WriteLine("Doing more work is Main"); //} ///当BeginInvoke处理完数据后调用AsyncCallback ///通过次线程通知主线程,这样子比主线程频繁询问次线程要好些。 IAsyncResult IResuit = d.BeginInvoke(2, 3, new AsyncCallback(AddComplete), null); //int AsyncResuit = d.EndInvoke(IResuit); //Console.WriteLine("2+4 is={0}", AsyncResuit); Console.ReadKey(); } static void AddComplete(IAsyncResult resut) { Console.WriteLine("addComplete线程ID:{0}",Thread.CurrentThread.ManagedThreadId); Console.WriteLine("you addition is complete"); /// AsyncResult定义在了System.Runtime.Remoting.Messaging; /// 该类的mydelegate返回了原始异步委托的应用,这个地方就是 /// public delegate int mydelegate(int x, int y); /// 这样子写的原因是BeginInvoke处理完了后,会调用AsyncCallback,但是他访问不到定义在Main中的EndInvoke AsyncResult r = (AsyncResult)resut; mydelegate b = (mydelegate)r.AsyncDelegate; Console.WriteLine(b.EndInvoke(resut)); } static int Add(int x, int y) { Console.WriteLine("Add方法中正在执行的线程ID:{0}",Thread.CurrentThread.ManagedThreadId); //暂停一下,模拟一个耗时的操作 Thread.Sleep(5000); return x + y; } }