JS——如果数组中的信息存在多个相同的属性，那么则将这些相同的信息放到同一个children中。

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var arr = [                    {name: '张三', age: 10, sex: '男'},                    {name: '李四', age: 10, sex: '男'},                    {name: '钱五', age: 11, sex: '女'},                    {name: '赵六', age: 12, sex: '女'},                    {name: '王七', age: 10, sex: '男'},                ]                // // 针对arr,根据相同的age 得出如下结果：                // result = [                //     {name: '混合装大保健', age: '******', sex: '你猜', children: [                //        {name: '张三', age: 10, sex: '男'},                //        {name: '李四', age: 10, sex: '男'},                //        {name: '王七', age: 10, sex: '男'},                //     ]},                //     {name: '钱五', age: 11, sex: '女'},                //     {name: '赵六', age: 12, sex: '女'},                // ]                  // Ⅰ:解（8号技师为你服务）：                let obj = {};                for( let item of arr){                    if( !obj[`${ item.age }`]){                        obj[`${ item.age }`] = {                            name: item.name,                            age: item.age,                            sex: item.sex,                            children: [ item],                        }                    }else {                        obj[`${ item.age }`]['children'].push( item);                    }                }                let _newArr = Object.values( obj);  // 通过Object.values() 得出以属性值为基准的集合。例如：var obj = { 0: 'a', 1: 'b', 2: 'c' }; console.log(Object.values(obj)); // 得出 ['a', 'b', 'c']                // console.log('~~ 看看：', _newArr);                // 得出如下结果:                // [                //     {                //         "name": "张三","age": 10,"sex": "男","children": [                //             {"name": "张三","age": 10,"sex": "男"},                //             {"name": "李四","age": 10,"sex": "男"},                //             {"name": "王七","age": 10,"sex": "男"}                //         ]                //     },                //     {"name": "钱五","age": 11,"sex": "女","children": [                //             {"name": "钱五","age": 11,"sex": "女"}                //         ]                //     },                //     {"name": "赵六","age": 12,"sex": "女","children": [                //             {"name": "赵六", "age": 12,"sex": "女"}                //         ]                //     }                // ]                                 // ...Ⅱ:进一步处理(贵客请进屋)。如果age只存在一个，那么将该信息中的children删除；并对非一个的信息行做处理。                _newArr.forEach( item => {                    if( item.children.length === 1 && item.age === item.children[ 0].age) {                        delete item.children;                    }else {                        item.name = '混合装大保健';                        item.age = '******';                        item.sex = '你猜';                    }                });                // console.log('最后看下：', _newArr); // 得出结果即为上述所说。